When acids react with metals they produce?

scoundrel [369]

Answer:

$2Al (s) + 3CuCl2( aq) --> 2AlCl3 (aq) + 3Cu(s)$

Explanation:

The main thing for this equation is to follow the amount on each side. Count each element on each side. Then by looking at the numbers figure out what numerical digit would make them equal.

For example:

On the left we have

Cu=1 and Cl=2.

But on the right we have

Cu=1 and Cl=3.

In order for them to be the same, we must add a coefficient of 3 to CuCl2 (aq0 on the left and a coefficient of 3 to Cu(s) on the right.

6 0

3 years ago

Bob is investigating whether the density of water changes with temperature. Which of the following variables should he change in

LekaFEV [45]

Answer:

temperature of the water

Explanation:

Density is defied as mass divided by the volume. To investigate how the density of water change with temperature, Bob have the change the temperature and read the volume and mass of the investigated sample.

Even if there is a different salt content between booted water or tap water and have an influence on the density (compared with pure water), this difference is not so big so the change in density with temperature can be determined. Considering that the experiment do not require extreme accuracy, any type of water may be used (bottled water of tap water).

7 0

4 years ago

2. In contrast to Venus, the coldest temperature yet measured on the surface of

Leviafan [203]

38K

-391°F

Explanation:

Given temperature:

Temperature of Triton = -235°C

Unknown:

Surface temperature of Triton in °F and Kelvin

Solution:

Temperature is the degree of hotness or coldness of a body.

It is usually measured using units of kelvin, degree Celsius and degree Fahrenheit.

tK = 273 + t°C from °C to K

t°F = $\frac{9}{5}$ t°C + 32

tk = temperature in kelvin

t°C = temperature in Celsius

t°F = temperature in Fahrenheit

tK = 273 + (-235) = 38K

t°F = $\frac{9}{5}$ x (-235) + 32 = -423 + 32 = -391°F

learn more:

Heat and temperature brainly.com/question/914750

#learnwithBrainly

7 0

4 years ago

A particular atom contains 29 electrons, 34 neutrons, and 29 protons. what is the identity of this element and what is its atomi

IgorLugansk [536]

Answer:

Identity = Copper

Atomic Number = 29

Explanation:

Given Data:

Number of Electrons = 29

Number of Neutrons = 34

Number of Protons = 29

Identity and atomic number of Element:

This element can be identified by using two sources, i) Atomic Number ii) Electronic Configuration.

Atomic Number is defined as the number of protons present in the nucleus of an element. As the given number of protons are 29, therefore, the atomic number of this element is also 29.

Secondly, if the element is in neutral state then its number of protons must be equal to the number of electrons present in it. So, in neutral state this element will contain 29 electrons. Therefore, the electronic configuration is as follow,

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d⁹

Now using electronic configuration one can easily identify the position of this element in periodic table. As the valence shell is 4, so it belongs to period 4 and there are 9 electrons in d-subshell so it belongs to transition elemnts and transition element with 9 electrons in d shell is Copper. Also, the stable electronic configuration of copper is written as,

1s², 2s², 2p⁶, 3s², 3p⁶, 4s¹, 3d¹⁰

5 0

3 years ago

9. Calculate the specific heat capacity of titanium if a 43.56 g sample absorbs 0.476 kJ as its temperature changes from 20.5 oC

Shalnov [3]

Answer:

c = 0.528 J/g.°C

Explanation:

Given data:

Mass of titanium = 43.56 g

Heat absorbed = 0.476 KJ = 476 j

Initial temperature = 20.5°C

Final temperature = 41.2°C

Specific heat capacity = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 41.2°C - 20.5°C

ΔT = 20.7 °C

476 J = 43.56 g × c × 20.7 °C

476 J = 901.692 g.°C × c

c = 476 J / 901.692 g.°C

c = 0.528 J/g.°C

8 0

3 years ago