Answer:A
Explanation:I hope I’m right
Pretty sure the force of gravity increases as the object does.
Answer:
ozone (O3): inorganic
methane (CH4): organic
aluminum hydroxide (Al(OH)3): inorganic
butane (C4H10): organic
carbon monoxide (CO): inorganic
Explanation:
An inorganic compound is typically a chemical compound that lacks carbon–hydrogen bonds, that is, a compound that is not an organic compound. Some simple compounds that contain carbon are often considered inorganic. Examples of inorganic compounds include carbon monoxide , carbon dioxide , carbonates, carbides , cyanides, cyanates, and thiocyanates. Most of these compounds are normal parts of mostly organic systems, including living organisms. When a chemical substance is classified as inorganic, it does not necessarily mean that it does not occur within
living things.
Organic compounds typically contain the carbon-hydrogen bonds. The carbon atoms often catenate and most organic substances occur in living systems and are products of biochemical reactions in living organisms. However, organic substances can also be synthetic and can be prepared in the laboratory.
Answer:
2.29 m.
Explanation:
The following data were obtained from the question:
Mass of KOH = 42.3 g
Molar mass of KOH = 56.11 g/mol
Mass of water = 329 g
Molality of KOH = ?
Next, we shall determine the number of mole in 42.3 g of KOH. This can be obtained as follow:
Mass of KOH = 42.3 g
Molar mass of KOH = 56.11 g/mol
Mole of KOH =?
Mole = mass /Molar mass
Mole of KOH = 42.3/56.11
Mole of KOH = 0.754 mole
Next, we shall convert 329 g of water to kilogram (kg). This can be obtained as follow:
1000 g = 1 kg
Therefore,
329 g = 329 g /1000 g × 1 kg
329 g = 0.329 kg
Therefore, 329 g of water is equivalent to 0.329 kg
Finally, we shall determine the molality of the KOH solution ad follow:
Molality is defined as the mole of solute per unit kilogram of solvent (water) i.e
Molality = mole/ mass (kg) of water
Mole of KOH = 0.754 mole.
Mass of water = 0.329 kg.
Molality = mole/ mass (kg) of water
Molality = 0.754/0.329
Molality = 2.29 m
Therefore, the molality of the KOH solution is 2.29 m.
Answer:
14.64 grams of carbon
Explanation:
The Molecular formula of Glucose is C₆H₁₂O₆.
From the molecular formula, the Molar mass of Glucose is,
Mass of Carbon in Glucose = 6*12 = 72.
Mass of Hydrogen in Glucose = 12*1 = 12.
Mass of Oxygen in Glucose = 6*16 = 96.
Molar mass of Glucose = 72+12+96 = 180 grams.
180 grams of Glucose contains 72 grams of Carbon.
How many grams of Carbon are there in 36.6 grams of Glucose.
180 --> 72
36.6 --> ?
Let it be 'x' grams
Then, by Criss Cross, (x)(180) = (36.6)(72) => x = 14.64 grams.
Therefore 14.64 grams of carbon are there in 36.6 grams in glucose.
