Answer:
The IUPAC name of given compound is 3−5−ethyl−5−−3−methylheptane. Explanation: The parental chain is of 7 carbons with single bonds hence it is heptane. Two substituents ethyl and methyl group are attached from an equal distance. Hence according to the alphabetical order preference, counting starts from carbon which is close to an ethyl group.
Frequency = velocity (aka speed) / wave length
Answer:
Mass in kg = 4.7*10^19 kg
Mass in tons = 5.2*10^16 tons
Explanation:
<u>Given:</u>
Total volume of sea water = 1.5*10^21 L
Mass % NaCl in seawater = 3.1%
Density of seawater = 1.03 g/ml
<u>To determine:</u>
Total mass of NaCl in kg and in tons
<u>Calculation:</u>
Unit conversion:
1 L = 1000 ml
The volume of seawater in ml is:
![=\frac{1.5*10^{21}L*1000ml }{1L} =1.5*10^{24} ml](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1.5%2A10%5E%7B21%7DL%2A1000ml%20%7D%7B1L%7D%20%3D1.5%2A10%5E%7B24%7D%20ml)
![Mass\ seawater = Density*volume = 1.03g/ml*1.5*10^{24} ml=1.5*10^{24}g](https://tex.z-dn.net/?f=Mass%5C%20seawater%20%3D%20Density%2Avolume%20%3D%201.03g%2Fml%2A1.5%2A10%5E%7B24%7D%20ml%3D1.5%2A10%5E%7B24%7Dg)
![Mass\ NaCl\ in\ seawater = \frac{3.1}{100}*1.5*10^{24} g=4.7*10^{22} g](https://tex.z-dn.net/?f=Mass%5C%20NaCl%5C%20in%5C%20seawater%20%3D%20%5Cfrac%7B3.1%7D%7B100%7D%2A1.5%2A10%5E%7B24%7D%20%20g%3D4.7%2A10%5E%7B22%7D%20g)
To convert mass from g to Kg:
1000 g = 1 kg
![Mass\ seawater(kg) = \frac{4.7*10^{22}g*1kg }{1000g} =4.7*10^{19} kg](https://tex.z-dn.net/?f=Mass%5C%20seawater%28kg%29%20%3D%20%5Cfrac%7B4.7%2A10%5E%7B22%7Dg%2A1kg%20%7D%7B1000g%7D%20%3D4.7%2A10%5E%7B19%7D%20kg)
To convert mass from g to tons:
1 ton = 9.072*10^6 g
![Mass\ seawater(tons) = \frac{4.7*10^{22}g*1ton }{9.072*10^{6}g } =5.2*10^{16} tons](https://tex.z-dn.net/?f=Mass%5C%20seawater%28tons%29%20%3D%20%5Cfrac%7B4.7%2A10%5E%7B22%7Dg%2A1ton%20%7D%7B9.072%2A10%5E%7B6%7Dg%20%7D%20%3D5.2%2A10%5E%7B16%7D%20tons)
Answer:
D
Explanation:
John is not a very good businessman.
:D