Iodine- in most cleaning solutions
Answer:
5.25 g NaF
Step-by-step explanation:
We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 41.99
Na₂SiO₃ + 8HF ⟶ H₂SiF₆ + 2 NaF + 3H₂O
n/mol: 8
(1) Calculate the moles of NaF
The molar ratio is 2 mol NaF/8 mol HF.
Moles of F = 0.500 mol HF × (2 mol Na₂SiO₃/8 mol HF)
Moles of Na₂SiO₃ = 0.125 mol Na₂SiO₃
(2) Calculate the mass of NaF
Mass of NaF = 0.125 mol NaF × (41.99 g Na₂SiO₃/1 mol Na₂SiO₃)
Mass of NaF = 5.25 g NaF
Answer:
3.5 atm
Explanation:
Given data
- Initial pressure (P₁): 47.9 atm
- Initial volume (V₁): 21 L
We can find the maximum pressure that the gas can exert (final pressure) using Boyle´s law.
P₁ × V₁ = P₂ × V₂
P₂ = P₁ × V₁ / V₂
P₂ = 47.9 atm × 21 L / 290 L
P₂ = 3.5 atm
Answer:
FC of C = -1
General Formulas and Concepts:
- Lewis Dot Structures
- Resonance Structures
- Formal Charge: FC = # of valence e⁻ - # of lone e⁻ - # of bonds
Explanation:
<u>Step 1: Define</u>
Carbon (C)
- 4 valence e⁻
- 2 lone e⁻
- 3 bonds
Oxygen (O)
- 6 valence e⁻
- 2 lone e⁻
- 3 bonds
<u>Step 2: FC of C</u>
- Substitute: FC = 4e⁻ - 2e⁻ - 3
- Subtract: FC = -1