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Sloan [31]
3 years ago
15

Why can’t cold air hold much water vapor?

Chemistry
1 answer:
Andru [333]3 years ago
4 0
Warm air can “hold” more water vapor than cool air because as the air warms its molecules move farther apart, making room for more molecules. This leads to the idea that as air cools its molecules move closer together, “squeezing” out water vapor.
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Please help :,) I’m being timed
vova2212 [387]

Answer:

B

Explanation:

6 0
3 years ago
The British gold sovereign coin is an alloy of gold and copper having a total mass of 7.988 g, and is 22-karat gold. (a) Find th
jonny [76]

Answer:

(a) Mass of gold = 0.0073223 kg.

(b) V of gold 3.79 x 10⁻⁷ m³ & ∴ V of copper = 7.438 x 10⁻⁸ m³.

(c) The density of the British sovereign coin 17,620 kg/m³.

Explanation:

<em>(a) Find the mass of gold in the sovereign in kilograms using the fact that the number of karats = 24 (mass of gold)/(total mass). </em>

<em></em>

∵ the number of karats = 24 (mass of gold)/(total mass)

the number of karats = 22-karat gold,

mass of gold = ??? g,

total mass = 7.988 g.

<em>∴ mass of gold = (the number of karats)(total mass)/24 =</em> (22)(7.988 g)/(24) = 7.3223 g = <em>0.0073223 kg.</em>

<em></em>

<em>(b) Calculate the volumes of gold and copper, respectively.</em>

∵ Mass of coin = 7.988 g.

∵ mass of gold = 7.3223 g.

∴ mass of Cu = Mass of coin - mass of gold = 7.988 g - 7.3223 g = 0.6657 g = 0.6657 x 10⁻³ kg.

  • To find the volume of Copper and gold, we can use the relation:

<em>V = m/d.</em>

where, V is the volume of the material,

m is the mass of the material,

d is the density of the material.

  • For gold:

Density of gold = 19,320 kg/m³, mass of gold = 0.0073223 kg.

∴ V of gold = m/d = (0.0073223 kg)/(19,320 kg/m³) = 3.79 x 10⁻⁷ m³.

 

  • For copper:

Density of copper = 8,950 kg/m³, mass of copper = 0.6657 x 10⁻³ kg.

∴ V of copper = m/d = (0.6657 x 10⁻³ kg)/(8,950 kg/m³) = 7.438 x 10⁻⁸ m³.

<em>(c) Calculate the density of the British sovereign coin. kg/m³.</em>

  • To find the density of the British sovereign coin, we can use the relation:

<em>d = m/V.</em>

mass of the British sovereign coin = 7.988 g = 0.007988 kg.

Volume of the British sovereign coin = V of gold + V of copper = (3.79 x 10⁻⁷ m³) + (7.438 x 10⁻⁸ m³) = 4.534 x 10⁻⁷ m³.

∴ Density of the British sovereign coin = m/V = (0.007988 kg)/(4.534 x 10⁻⁷ m³) = 17,620 kg/m³.

5 0
3 years ago
The temperature of a sample of gas in a steel
Snezhnost [94]

Answer:

P_2=51.7kPa

Explanation:

Hello,

In this case, we apply the Gay-Lussac's law which allows us to understand the pressure-temperature behavior via a directly proportional relationship:

\frac{P_1}{T_1}=\frac{P_2}{T_2}

Thus, since we are asked to compute the final pressure we solve for it in the previous formula, considering the temperature in absolute Kelvin units:

P_2=\frac{P_1T_2}{T_1}=\frac{30.0kPa*(25.0+273)K}{(-100.0+273)K} \\\\P_2=51.7kPa

Best regards.

3 0
3 years ago
Read 2 more answers
What is the first principle energy level called
Firlakuza [10]
Answer is s orbital. Hopes this helps
6 0
3 years ago
Read 2 more answers
The ksp of cadmium hydroxide, cd(oh)2, is 7.20 × 10-15. calculate the solubility of this compound in g/l.
olga nikolaevna [1]
When the solubility is the amount of solute that dissolved in a unit volume of the solvent.

and when the balanced reaction equation is:

so, by using the ICE table:

            Cd(OH)2(s) ↔  Cd2+  +  2OH- 

initial                               0             0

change                          +X           +2X

Equ                                  X             2X

so the Ksp expression = [Cd2+] [OH-]^2 

and we have Ksp = 7.2 x 10^-15

and when we assume the solubility = X
  
by substitution:

7.2 x 10^-15 = (X) (2X)^2

7.2 x 10^-15 = X*4X^2

7.2 x 10^-15 = 4X^3

∴X = ∛(7.2x10^-15)/4

      = 1.22 x 10^-5 M

∴ the solubility = X = 1.22 x 10^-5 M
6 0
3 years ago
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