Polar molecules exhibit an unequal balance of charges between the individual elements of the compound. This is brought about by the large difference in their electronegativities. The H atom has the least amount of electronegativity. Then, it is a known periodic trend, that as you go downwards in a group, electronegativity decreases, and increase as you go from left to right. Thus, you can deduce that the most electronegative elements are found in the upper right corner which includes O, N and F atoms. Any bond created between Hydrogen and any of O, N and F atoms is a polar bond.
Answer:
Cyclopropane has a planar carbon back bone while propane does not
Explanation:
We have to recognize that in straight chain saturated organic compounds, carbon atoms have a tetrahedral geometry. Each carbon atom is bonded to four other atoms.
However, carbon atoms in cyclic compounds are also sp3 hybridized with each carbon bonded to only four other atoms but the ring system is highly strained.
Cyclopropane is a necessarily planar molecule with a bond angle that is far less than the expected tetrahedral bond angle due to strain in the molecule. Hence, the carbon atoms may have have a "planar backbone".
Explanation:
According to Boyle's law, pressure of a gas is inversely proportional to its volume at constant temperature and moles.
Mathematically, P = 
where, k = proportionality constant
Also, formula for initial pressure and volume is as follows.
or, 
= 
= 30 atm L
Now, we will calculate the value of 
as follows.
= 
= 30 atm L
Hence, as 
this means that it signifies that gas obeys boyle's law.
Required; released.
Think of a bond as like a wooden board. You have to put in energy to break it.
