The answer is 615.91 grams of <span>n2f4
Solution:
225g F2 x [(1molF2)/(38gramsF2)] x [</span>(1molF2)/(1molN2F4)] x [(104.02 grams N2F4)/(1molN2F4)]
=615.91 grams
Answer:
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Explanation:
Fossils are the preserved remains, or traces of remains, of ancient organisms. Fossils are not the remains of the organism itself! They are rocks. A fossil can preserve an entire organism or just part of one. Bones, shells, feathers, and leaves can all become fossils.
The binding energy in MeV per atom is - 63284.56 Mev.
The amount of energy needed to detach a particle from a system of particles or to disperse every particle in the system is known as the binding energy. Subatomic particles in atomic nuclei, electrons attached to atom's nuclei, and atoms and ions bonded together in crystals are three examples of where binding energy is very relevant.
If we have a nucleus with Z protons and N neutrons and mass MA, where A = Z + N then its binding energy in MeV is given by: Eb(MeV) = (Zmp + Nmn - MA) x 931.494 MeV/u
Mass of atom = 69.955264 amu
Mass of proton = 1.007825 amu
Mass of neutron = 1.008665 amu
Binding energy, Mev = (Zmp + Nmn - M) × 931.494MeV/u
= ( 1.007825 + 1.008665 - 69.955264) × 931.494
= - 67.938774 × 931.494
= - 63284.56 Mev
Therefore, the binding energy in MeV per atom is - 63284.56 Mev.
Learn more about binding energy here:
brainly.com/question/16795451
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Answer:
Percent yield is 25%
Explanation:
Information given is
Actual yield is 25 g
But the yield should be 100 g
The percent yield is defined as the ratio of the actual yield and the predicted yield it means that out of the predicted yield what percentage of the actual yield is obtained
∴ Percent yield = (Actual yield ÷ Predicted yield) × 100
In case of the given problem the percent yield will be
(25÷100) × 100 = 25%
∴ Percent yield = 25%
Answer:
100.5 ≈ 101
Explanation:
Km for S1 = 2.0 mM
Km for S2 = 20 mM
Given that : S1 = S2 = hence Vmax for either S1 or S2 can represent
The Vmax can be calculated using the data Given and equation below
Vo = Vmax [s] / ( Km + [s] ) ------ (1)
Vo = 0.5
[s] = 0.1 mM
km = 20 mM
making Vmax subject of equation 1
Vmax = 0.5 ( 20.1 mM) / (0.1 mM )
= 100.5 ≈ 101
