Answer:
Mg donates two electrons to O
Explanation:
Lewis dot notation uses dots and crosses to represent valence electrons on atoms.
Magnesium is a metal and would donate or lose electrons during bonding.
Oxygen is a non metal and would gain electrons during bonding.
The correct option is;
Mg donates two electrons to O
Answer:
![CH _{4}+ 2O _{2} → CO _{2} + 2H _{2}O](https://tex.z-dn.net/?f=CH%20_%7B4%7D%2B%202O%20%20_%7B2%7D%20%E2%86%92%20CO%20_%7B2%7D%20%2B%202H%20_%7B2%7DO)
for the balanced equation
![from \: the \: equation \\ 1 \: mole \: of \: methane \: gives \: 1 \: mole \: of \: carbon \: dioxide \\ 7.4 \: moles \: of \: carbon \: dioxide \: will \: be \: given \: by \: (7.4 \times 1)moles \: of \: methane \\ = 7.4\: moles \: of \: methane \\ \\ since \: moles \: of \: oxygen \: double \: those \: of \: methane \\ moles \: of \: oxygen \: = 7.4\times 2 \\ = 14.8 \: moles \: of \: oxygen](https://tex.z-dn.net/?f=from%20%5C%3A%20the%20%5C%3A%20equation%20%5C%5C%201%20%5C%3A%20mole%20%5C%3A%20of%20%5C%3A%20methane%20%5C%3A%20gives%20%5C%3A%201%20%5C%3A%20mole%20%5C%3A%20of%20%5C%3A%20carbon%20%5C%3A%20dioxide%20%5C%5C%207.4%20%5C%3A%20moles%20%5C%3A%20of%20%5C%3A%20carbon%20%5C%3A%20dioxide%20%5C%3A%20will%20%5C%3A%20be%20%5C%3A%20given%20%5C%3A%20by%20%5C%3A%20%287.4%20%5Ctimes%201%29moles%20%5C%3A%20of%20%5C%3A%20methane%20%5C%5C%20%20%3D%207.4%5C%3A%20moles%20%5C%3A%20of%20%5C%3A%20methane%20%5C%5C%20%20%5C%5C%20%20since%20%5C%3A%20moles%20%5C%3A%20of%20%5C%3A%20oxygen%20%5C%3A%20double%20%5C%3A%20those%20%5C%3A%20of%20%5C%3A%20methane%20%5C%5C%20moles%20%5C%3A%20of%20%5C%3A%20oxygen%20%5C%3A%20%20%3D%207.4%5Ctimes%202%20%5C%5C%20%20%3D%2014.8%20%5C%3A%20moles%20%5C%3A%20of%20%5C%3A%20oxygen)
Well, it was to capture Japanese controlled islands until the Japanese came into range of the American Bombers, which was different from them going after the Japanese and invading the islands.
Answer:
The concentration of the copper (II) sulfate solution is 2.06 * 10^2 μmol/L or 2.06 * 10^2 μM
Explanation:
The concentration of a solution is the amount of solute dissolved in a given volume of solution. In this case, the concentration of the copper(II) sulfate solution in micromoles per liter (symbol ) is the number of micromoles of copper(II) sulfate dissolved in each liter of solution. To calculate the micromoles of copper(II) sulfate dissolved in each liter of solution you must divide the total micromoles of solute by the number of liters of solution.
Here's that idea written as a formula: c= n/V
where c stands for concentration, n stands for the total micromoles of copper (II) sulfate and V stands for the total volume of the solution.
You're not given the volume of the solution in liters, but rather in milliliters. You can convert milliliters to liters with a unit ratio: V= 150. mL * 10^-3 L/ 1 mL = 0.150 L
Next, plug in μmol and liters into the formula to divide the total micromoles of solute by the number of liters of solution: c= 31 μmol/0.150 L = 206.66 μmol/L
Convert this number into scientific notation: 2.06 * 10^2 μmol/L or 2.06 * 10^2 μM