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AnnyKZ [126]
2 years ago
8

. Calculate the pH and the pOH of each of the following solutions at 25 °C for which the substances ionize completely:

Chemistry
1 answer:
barxatty [35]2 years ago
5 0
A. HCl:
pH= -log [H3O+]
PH=-log (0.200)
= 0.699

poH= 14-0.699
= 13.301

b. NaOH:
PoH= -log [OH-]
= -log (0.0143)
= 1.845
pH= 14-poH
= 14- 1.845
= 12.16

c. HNO3:
PH= -log[H3O+]
=-log(3.0)
= -0.4771
poH= 14-pH
= 14-9-0.4771
= 14.4771

pH= -0.4771, poH= 14.4771

d. [Ca(OH)2] = 0.0031M
[OH-]= 2X0.0031
[OH-] = 0.0062M

PoH= - log[OH-]
=-log(0.0062)
=-log(6.2x10-3)
=-(-2.21)
= 2.21
PH=14-poH
=14-2.21
=11.79
POH=2.21, PH= 11.79
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Answer:

The configuration of the atom would be 2-8-2.

Explanation:

Any atom of an element combines with other element to complete its octet and become stable.

The electron configuration of the given atom is 2-8-6. That means the atom has 6 electrons in its outermost shell. To become stable the atom should have 8 electrons in its outermost shell. The given atom has 6 electrons so it either lose 6 electrons or gain 2 electrons to complete its octet.

But we know the atom having 5,6,7 electrons in its outermost shell they do not lose, they gain either 3 or 2 or 1 electrons to complete its octet.

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8 0
3 years ago
The measured value 24.00 g has an uncertainty of?
Orlov [11]

Answer:

±0.005 g

Explanation:

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It may be greater, depending on random or personal errors

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If the measured value were 20.006, the display would round up to 20.01.

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6 0
3 years ago
If 9.6 X 1021 molecules of hydrogen are reacted with excess nitrogen, how many liters of ammonia can be produced at STP?
diamong [38]

The volume of NH₃ produced at STP : 0.237 L

<h3>Further explanation</h3>

Reaction

N₂ + 3H₂ → 2NH₃

1 mol = 6.02 x 10²³ particles

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\tt \dfrac{9.61\times 10^{21}}{6.02\times 10^{23}}=1.596\times 10^{-2}~moles

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mol NH₃ :

\tt \dfrac{2}{3}\times 1.596\times 10^{-2}=0.0106

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). <em>At STP, Vm is 22.4 liters/mol.</em>

The volume of NH₃ :

\tt 0.0106\times 22.4=0.237~L

<em />

8 0
2 years ago
​If 250.0 mL of a 0.96 M solution of acetic acid (C 2H 4O 2) are diluted to 800.0 mL, what will be the approximate molarity of t
adoni [48]

Answer:

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7 0
3 years ago
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