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aleksandrvk [35]
3 years ago
14

The Space Shuttle does not directly inject into its prescribed mission orbit. Rather, themain engine shutdown occurs at the apog

ee of an elliptical orbit with 100-km altitudeand the external tank is discarded. Perigee of this orbit is at 30-km altitude. After thetank is released, the Shuttle uses its orbital maneuvering system (OMS) to maneuverinto an elliptical orbit with perigee at 100-km altitude and apogee at 250-km altitude.This is called the OMS-1 burn. At the new apogee, the Shuttle performs the OMS-2burn to circularize into the 250-km altitude mission orbit. Calculate:
(a) the burnout speed at apogee in the external tank disposal orbit;(b) the ΔV required for the OMS-1 maneuver;(c) the ΔVrequired for the OMS-2 maneuver;(d) if launching from the Kennedy Space Center, without a plane change maneuver,what is the range of inclinations possible for the Shuttle mission orbit? Why?

Physics
1 answer:
iris [78.8K]3 years ago
8 0

Answer:

(a) burnout speed at apogee in the external tank disposal orbit=7.82 km/sec

(b) ΔV required for the OMS-1 =0.066 km/sec

(c) ΔV required for the OMS-2 =0.045 km/sec

(d) This part of the question is explained in detailed way in the attached file.

Explanation:

Detailed explanation of all the parts of the question are given in attached files.

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A steel piano wire, of length 1.150 m and mass of 4.80 g is stretched under a tension of 580.0 N.the speed of transverse waves on the wire would be  372.77 m/s

<h3>What is a sound wave?</h3>

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For calculating the wave velocity of the sound waves generated from the piano can be calculated by the formula

V= √F/μ

where v is the wave velocity of the wave travel on the string

F is the tension in the string of piano

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The μ is the mass per unit length of the string would be

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