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<span><span>The
best and most correct answer among the choices provided by the question is </span>B.-2.71 V.</span>
Mg2+(aq) + 2e- -> Mg(s) E=-2.37 V
Cu2+(aq) + 2e- -> Cu(s) E =+ 0.34 V
Since Cu is acting as the anode, the equation needs to be
reversed.
Cu(s) -> Cu2+(aq) + 2e- E =- 0.34 V
Ecell= -2.37 V+ (- 0.34 V) = -2.71 V
<span><span>
</span><span>Hope my answer would be a great help for you. </span> </span>
<span> </span>
<u>Answer:</u> The voltage needed is 35.7 V
<u>Explanation:</u>
Assuming that the resistors are arranged in parallel combination.
For the resistors arranged in parallel combination:

We are given:

Using above equation, we get:

Calculating the voltage by using Ohm's law:
.....(1)
where,
V = voltage applied
I = Current = 3.75 A
R = Resistance = 
Putting values in equation 1, we get:

Hence, the voltage needed is 35.7 V
Answer:5.21 N
Explanation:
Given
B=5.210 T
I=2 A
L=0.5 m
Given Wire is perpendicular to Magnetic field




F=5.210 N
as 1 Tesla =1 N/A/m
Acceleration = (final velocity-initial velocity)/time
5 = (v-0)/20
v = 100m/s