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sasho [114]
3 years ago
10

3 light bulbs with resistances of 20, 15, and 45 are powered by a 9v battery. What type of circuit should the light bulbs be pla

ced in for the most power
Physics
1 answer:
Katyanochek1 [597]3 years ago
8 0

Answer:The light bulb with the 15ohm resistance will have more power

Explanation:

Resistance is inversely proportional to current, so as the resistance increases the current decreases,so there 15ohm resistance bulb will be powered more because of it low resistance

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What is the voltage of the electrochemical cell written as: Cu(s) | Cu2+(aq) || Mg2+(aq) | Mg(s)?
erma4kov [3.2K]
Thank you for posting your question here at brainly. Feel free to ask more questions.  
<span><span>The best and most correct answer among the choices provided by the question is  </span>B.-2.71 V.</span>  
Mg2+(aq) + 2e- -> Mg(s) E=-2.37 V  

Cu2+(aq) + 2e- -> Cu(s) E =+ 0.34 V  

Since Cu is acting as the anode, the equation needs to be reversed.  

Cu(s) -> Cu2+(aq) + 2e- E =- 0.34 V  

Ecell= -2.37 V+ (- 0.34 V) = -2.71 V   <span><span>

</span><span>Hope my answer would be a great help for you. </span> </span> <span> </span>
4 0
4 years ago
Voltage needed to raise current to 3.75a using 20,20,200 resistor set
Varvara68 [4.7K]

<u>Answer:</u> The voltage needed is 35.7 V

<u>Explanation:</u>

Assuming that the resistors are arranged in parallel combination.

For the resistors arranged in parallel combination:

\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}

We are given:

R_1=20\Omega\\R_2=20\Omega\\R_3=200\Omega

Using above equation, we get:

\frac{1}{R}=\frac{1}{20}+\frac{1}{20}+\frac{1}{200}\\\\\frac{1}{R}=\frac{10+10+1}{200}\\\\R=\frac{200}{21}=9.52\Omega

Calculating the voltage by using Ohm's law:

V=IR         .....(1)

where,

V = voltage applied

I = Current = 3.75 A

R = Resistance = 9.52\Omega

Putting values in equation 1, we get:

V=3.75\times 9.52\\\\V=35.7V

Hence, the voltage needed is 35.7 V

7 0
3 years ago
Read 2 more answers
A uniform magnetic field B=5.210 T is perpendicular to the plane of the paper (into the page). The current-carrying wire of valu
ehidna [41]

Answer:5.21 N

Explanation:

Given

B=5.210 T

I=2 A

L=0.5 m

Given Wire is perpendicular to Magnetic field

\theta =90^{\circ}

F=IL\times B

F=BIL sin\theta

F=5.210\cdot 2\cdot 0.5 sin(90)

F=5.210 N

as  1 Tesla =1 N/A/m

4 0
3 years ago
A train departs from its station at a constant acceleration of 5 m/s. What is the speed of the train at the end of 20s?
morpeh [17]
Acceleration = (final velocity-initial velocity)/time
5 = (v-0)/20
v = 100m/s
4 0
3 years ago
Read 2 more answers
Q. A train accelerates from 36 km/h to 54 km/h in 10 sec. (i) Acceleration (ii) The distance travelled by car.
Brrunno [24]

u=10m/s

v=15m/s

acceleration=

v_u/ t

5/10

0.5

5 0
3 years ago
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