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sasho [114]
3 years ago
10

3 light bulbs with resistances of 20, 15, and 45 are powered by a 9v battery. What type of circuit should the light bulbs be pla

ced in for the most power
Physics
1 answer:
Katyanochek1 [597]3 years ago
8 0

Answer:The light bulb with the 15ohm resistance will have more power

Explanation:

Resistance is inversely proportional to current, so as the resistance increases the current decreases,so there 15ohm resistance bulb will be powered more because of it low resistance

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Read 2 more answers
An automobile starter motor has an equivalent resistance of 0.0500Ω and is supplied by a 12.0-V battery with a 0.0100-Ω internal
alexandr1967 [171]

Answer

given,

resistance = 0.05 Ω

internal resistance of battery = 0.01 Ω

electromotive force = 12 V

a) ohm's law

        V = IR

     and volage

   V = \epsilon - Ir

now,

   IR = \epsilon - Ir

   I(R+r) = \epsilon

   I= \dfrac{\epsilon}{R+r}

inserting the values

   I= \dfrac{12}{0.05+0.01}

      I = 200 A

b) Voltage

   V = I R

   V = 200 x 0.05

   V = 10 V

c) Power

    P = I V

    P = 200 x 10 = 2000 W

d) total resistance = 0.05 + 0.09 = 0.14 Ω

 I= \dfrac{\epsilon}{R+r}

   I= \dfrac{12}{0.14+0.01}

     I = 80 A

     V = 80 x 0.05 = 4 V

     P = 4 x 80 = 320 W

6 0
3 years ago
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