Answer:
The observer sees the space-probe 9.055m long.
Explanation:
Let be the length of the space-probe when measured at rest, and
be its length as observed by an observer moving at velocity
, then
Now, we know that and
, and putting these into
we get:
Thus, an observer moving at 0.95c observes the space-probe to be 9.055m long.
Which of the following are characteristics of noble gases?
✅
✅
Answer:
The definition of that same given problem is outlined in the following section on the clarification.
Explanation:
The Q seems to be endless (hardly any R on the circuit). So energy equations to describe and forth through the inducer as well as the condenser.
Presently take a gander at the energy stored in your condensers while charging is Q.
⇒
So conclude C doesn't change substantially as well as,
When,
⇒
⇒
And therefore only half of the population power generation remains in the condenser that tends to leave this same inductor energy at 3/4 U.
Answer:
t = 1.659s
Explanation:
We can use the kinematics equations to solve this questions:
v = u + at
where v = Final Velocity, u = initial velocity, a = acceleration, t = time, s = displacement
a) Given information from the question,
u = (Convert km/h to m/s first)
a =
s = 35m
Now we can substitute these values into the 2nd kinematics equation to find v, final velocity.
b) Now we have the final velocity, we can substitute the values into the first kinematics equation to find t , the time taken.
v = u + at
22.761 = 19.444 + 2t
2t = 22.761 - 19.444
t =
t = 1.659s