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Ymorist [56]
4 years ago
6

What is meant by the term concentration?

Chemistry
1 answer:
steposvetlana [31]4 years ago
5 0

Answer:

the action or power of focusing one's attention or mental effort.

Explanation:

Keyword: <em>Focus </em>

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Kwame wants to measure the volume of water contained in a disposable foam coffee cup. Which units should he use?
tatyana61 [14]

The volume of water can be measured by different scale from a micro level to macro. The micro level water can be calculated by micro liter, where as the high quantity of liquid is expressed by gallon. To determine the volume of the water, which is small in grade one should use the milliliter(mL) unit. 1 mL is equivalent to 0.001 liter. The unit in which we are expressing the volume of any liquid should be simple and hand-able data. The volume of the water containing in a cup may be of 50-100 mL. Thus for this much volume using of macro or any other major unit will make the data complicated.    

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Answer:

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Explanation:

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3 years ago
True or false atoms of difference elements can combine to form compound?
motikmotik

It's true

There are thousands of combinations that can be put together to form a all sorts of compounds. That's the whole basis of inorganic chemistry. Organic chemistry is a little bit different. It is more restricted.

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3 years ago
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When a 0.235-g sample of benzoic acid is combusted in a bomb calorimeter, the temperature rises 1.643 ∘C . When a 0.275-g sample
andrew-mc [135]

Answer : The heat of combustion per mole of caffeine at constant volume is 76197.18 kJ/mole

Explanation :

First we have to calculate the specific heat calorimeter.

Formula used :

Q=m\times c\times \Delta T

where,

Q = heat of combustion of benzoic acid = 26.38 kJ/g = 26380 J/g

m = mass of benzoic acid = 0.235 g

c = specific heat of calorimeter = ?

\Delta T = change in temperature = 1.643^oC

Now put all the given value in the above formula, we get:

26380J/g=0.235g\times c\times 1.643^oC

c=68323.38J/^oC

Thus, the specific heat of calorimeter is 68323.38J/^oC

Now we have to calculate the heat of combustion of caffeine.

Formula used :

Q=c\times \Delta T

where,

Q = heat of combustion of caffeine = ?

c = specific heat of calorimeter = 68323.38J/^oC

\Delta T = change in temperature = 1.584^oC

Now put all the given value in the above formula, we get:

Q=68323.38J/^oC\times 1.584^oC

Q=108224.23J=108.2kJ

Now we have to calculate the moles of caffeine.

\text{Moles of caffeine}=\frac{\text{Mass of caffeine}}{\text{Molar mass of caffeine}}

Mass of caffeine = 0.275 g

Molar mass of caffeine = 194.19 g/mole

\text{Moles of caffeine}=\frac{0.275g}{194.19g/mole}=0.00142mol

Now we have to calculate the heat of combustion per mole of caffeine at constant volume.

\text{Heat of combustion per mole of caffeine}=\frac{108.2kJ}{0.00142mol}=76197.18kJ/mole

Therefore, the heat of combustion per mole of caffeine at constant volume is 76197.18 kJ/mole

4 0
3 years ago
How many moles are in 500.0cm^3 of oxygen gas at stp
Natalija [7]

Answer:

.02232 mole

Explanation:

At STP each 22.4 liters is a mole

.5 liters / 22.4 l/mole = .02232 mole

6 0
2 years ago
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