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3 years ago

Kwame wants to measure the volume of water contained in a disposable foam coffee cup. Which units should he use?

Chemistry

2 answers:

White raven [17]3 years ago

5 0

Answer:

Milliliter is the correct answer on e2020.

Explanation:

Just did the assignment.

tatyana61 [14]3 years ago

4 0

The volume of water can be measured by different scale from a micro level to macro. The micro level water can be calculated by micro liter, where as the high quantity of liquid is expressed by gallon. To determine the volume of the water, which is small in grade one should use the milliliter(mL) unit. 1 mL is equivalent to 0.001 liter. The unit in which we are expressing the volume of any liquid should be simple and hand-able data. The volume of the water containing in a cup may be of 50-100 mL. Thus for this much volume using of macro or any other major unit will make the data complicated.

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Answer to AP chem question

andrew11 [14]

Answer:

See the answer and explanation below, please.

Explanation:

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KN03 ( Potassium Nitrate)-->The nitratete suffix corresponds to the highest number of nytrogen oxidation (+5)

Fe 2 (C03)3 (Iron (III) Carbonate / Dihydrous Trioxide / Ferric Carbonate)-->The carbonate suffix corresponds to the highest number of carbon oxidation (+4)

Pb (Co2)2 (Lead carbonate (IV) / Lead trioxocarbonate (IV)))-->The carbonate suffix corresponds to the highest number of carbon oxidation (+4)

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3 years ago

What characteristics do atoms of argon-40, potassium-40, and calcium-40 have in common?

timurjin [86]

⁴⁰Ar
N(e)=18
N(p)=18
N(n)=40-18=22

⁴⁰K
N(e)=19
N(p)=19
N9n)=40-19=21

⁴⁰Ca
N(e)=20
N(p)=20
N(n)=40-20=20

4 0

3 years ago

Two Carnot engines are operated in series with the exhaust (heat output) of the first engine being the input of the second engin

OlgaM077 [116]

Answer:

(a) 140 F

(b) The temperature rise at the point where the heat is dumped is 2.51 degC

Explanation:

(a) Considering T1 the temperature of input of the first engine, T2 the temperature of the exhaust of the first engine (and input of the second engine) and T3 the exhaust of the second engine, if both engines have the same efficiency we have:

$\eta=1-\frac{T_1}{T2}=1-\frac{T_2}{T_3}$

The temperatures have to be expressed in Rankine (or Kelvin) degrees

$1-\frac{T_1}{T2}=1-\frac{T_2}{T_3}\\\\\frac{T_1}{T2}=\frac{T_2}{T_3}\\\\(T_2)^{2} =T_1*T_3\\\\T_2=\sqrt{T_1*T_3} =\sqrt{(459.67+260)*(459.67+40)}= \sqrt{719.67*499.67}\\\\ T_2=599 \, R= (599-459.67) ^{\circ} F=140^{\circ} F$

(b) The Carnot efficiency of the cycle is

$\eta_{c}=1-Th/Ts=1-(273+20)/(273+315)=0.502$

If the efficiency of the plant is 60% of the Carnot efficiency, we have

$\eta=0.6*\eta_{c}=0.6*0.502=0.302$

The heat used in the plant can be calculated as

$Q_i=W/\eta=750MW/0.302=2483MW$

And the heat removed to the heat sink is

$Q_o=Qi-W=2483-750=1733MW$

If the flow of the river is 165 m3/s, the heat per volume in the sink is

$\frac{Q_o}{f} =\frac{1733 MJ/s}{165 m3/s}= 10.5MJ/m3$

Considering a heat capacity of water C=4.1796 kJ/(kg*K) and a density ρ of 1000 kg/m3, the temperature rise of the water is

$\Delta Q=C*\Delta T\\\Delta T=(1/C)*\Delta Q\\\Delta T=(\frac{1}{4.1796\frac{kJ}{kgK} } )*10,500\frac{kJ}{m3}*\frac{1m3}{1000kg}\\\Delta T= 2.51 ^{\circ}C$

8 0

4 years ago

The uncertainty in the measurement 1500 m is

erastova [34]

Answer:

Its 1500 meters, which is equal to 0.9320568 miles. Hope this helps!

Explanation:

8 0

3 years ago

Which component in this mixture has the lowest density? A. glass. . B. water. . C. sawdust. . D. sand

Yuri [45]

The component in the mixture with the lowest density would be the component floating on the top of the mixture, i.e. the lightest in weight. Therefore, it would be the sawdust.

3 0

3 years ago

Read 2 more answers