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3 years ago

How can naphthalene be separated from a mixture of kbr and sand?

2 answers:

7 0

Put it in a beaker. Use a smaller beaker filled half way with ice and water and place in the larger one. It should be about an inch or two above the mixture. Heat over a Bunsen burner and the naphthalene will deposit on the bottom of smaller beaker.

And in this way, nephthalene be separated from the mixture of KBR and sand.

Fofino [41]3 years ago

7 0

Explanation:

A mixture of naphthalene in KBr and sand can be separated by heating as naphthalene has low boiling point. Hence, its volatility is high due to which it will easily escape out from the mixture.

So, vapors of naphthalene can be collected through sublimation. As a result, naphthalene will be separated out from the mixture.

Now, only KBr and sand is left in the mixture. So, water will be added in to this mixture due to which KBr will dissolve in it. And upon filtration sand will be separated out of this mixture.

Whereas upon heating the mixture of water and KBr, water will evaporate and crystals of KBr will be obtained. As a result, all the components of this mixture will be separated out.

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Why does the octet rule not always refer to a stable arrangement of eight valence electrons

bearhunter [10]

Answer:

Explanation:

The octet rule does not always refer to a stable arrangement of eight valence electrons because there are some element that do not have eight valence electrons yet they are stable. for example;

i) Helium, It has two valence electrons and it is a stable gas.

ii) Boron triflouride (BF3); it has six valence electrons (deficit valence electron) yet it is also stable.

iii) Phosphorus pentachloride (PCl5); it has more than eight valence electron and it is also stable.

For these few reasons it is not always advisable to say octet arrangement refer to stable eight valence electrons.

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3 years ago

A gas expands and does P-V work on the surroundings equal to 275 J. At the same time, it absorbs 216 J of heat from the surround

mafiozo [28]

Answer:

answer

Explanation:

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3 years ago

Balance the equation αC6H14(g)+βO2(g)→γCO2(g)+δH2O(g)

fenix001 [56]

Answer: The balanced reaction is:
2 C6H14(g)+ 19 O2(g) → 12 CO2(g)+ 14 H2O(g)

Note: While balancing the chemical reaction, care must be taken that total number atoms (of each type) on both reactant and product side must be same. In present case, there are 12 'C' atoms, 28 'H' atoms and 38 'O' atoms on both reactant and product side. Hence, the reaction is balanced.

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3 years ago

Read 2 more answers

PLEASE ANSWER CORRECTLY AND ONLY IF U KNOW! IS IT A B C OR D?!

almond37 [142]

Answer:

Explanation:

There are three states of mater; solid liquid and gas. The sold state is the difficult to compress while the gaseous state is quite easy to compress.

A gas is easily compressed because the particles in a gas are far apart from each other. A solid is difficult to compress because the particles of a solid are close together. From all the above statements, it is easily deducible that the compressibility property of a substance in a particular state of matter depends on the proximity of the particles to each other, hence the answer above.

8 0

3 years ago

Propane is often used to heat homes. The combustion of propane follows the following reaction: C3H8(g) + 5O2(g)  3CO2 (g) + 4H

swat32

Answer:

To release 7563 kJ of heat, we need to burn 163.17 grams of propane

Explanation:

Step 1: Data given

C3H8 + 5O2 -----------> 3CO2 + 4H2O ΔH° = –2044 kJ

This means every mole C3H8

Every mole of C3H8 produces 2044 kJ of heat when it burns (ΔH° is negative because it's an exothermic reaction)

Step 2: Calculate the number of moles to produce 7563 kJ of heat

1 mol = 2044 kJ

x mol = 7563 kJ

x = 7563/2044 = 3.70 moles

To produce 7563 kJ of heat we have to burn 3.70 moles of C3H8

Step 3: Calculate mass of propane

Mass propane = moles * Molar mass

Mass propane = 3.70 moles * 44.1 g/mol

Mass propane = 163.17 grams

To release 7563 kJ of heat, we need to burn 163.17 grams of propane

7 0

3 years ago