Running water. Streams, lakes, rivers, ponds, oceans- all affect the Earth's landscape.
The element symbol in chemistry comprises atomic number and mass number.
Atomic number is written on the top of element and mass number is written at the bottom.
For eg:
If Y is an element that is having atomic number a and mass number x. Then its denotion will be:
ᵃYₓ.
So here ⁹F₁₈.₉₉
Here 18.99 will denote mass number while 9 will denote atomic number.
Answer:
the % yield is 82%
Explanation:
Given the data in the question,
we know that;
Molar mass of benzil is 210.23 g·mol−1
Molar mass of dibenzyl ketone is 210.27 g·mol−1
Molar mass of tetraphenylcyclopentadienone is 384.5 g·mol−1
Now,
2.0 g benzil = 2 g / 210.23 g·mol−1 = 0.0095 mole
2.2 g dibenzyl ketone = 2.2 / 210.27 = 0.0105 mole
3.0 g of tetraphenylcyclopentadienone = 3 / 384.5 = 0.0078 mole
Now, the limiting reagent is benzil. 0.0095 mole can reacts wiyh 0.0095 mole of dibenzyl ketone
percentage yield = ( 0.0078 mole / 0.0095 mole ) × 100%
= 0.82 × 100%
= 82%
Therefore, the % yield is 82%
Answer: Cesium chloride dissolves in pure water has
> 0.
Explanation:
Entropy is the measure of randomness or disorder of a system. If a system moves from an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.
is positive when randomness increases and
is negative when randomness decreases.
a) 
As 2 moles of gas are converting to 1 mole of gas and 1 mole of liquid, the randomness decreases and hence
is negative.
b) 
As gas molecules are converting into aqueous and liquid form, the randomness decreases and hence
is negative.
c) lithium fluoride forms from its elements: 
As elements are combining to form a compound, the randomness decreases and hence
is negative.
d) Cesium chloride dissolves in pure water : 
As compound is dissociating into ions, the randomness increases and hence
is positive.
Answer:
Molality for this solution is 0.98 mol/kg
Explanation:
ΔT = Kf . m . i
Freezing point depression, here
ΔT = Freezing point of pure solvent - Freezing point of solution
i = Van't Hoff factor.
This solute, the amino acid glycine does not ionize, so the i in this case is 1
Let's replace the data given
0° - (-1.83°C) = 1.86 °C/m . m . 1
1.83°C = 1.86 °C/m . m . 1
1.83°C / 1.86 m/°C = 0.98 m