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Ray Of Light [21]
3 years ago
15

The scientific Method

Chemistry
1 answer:
allochka39001 [22]3 years ago
4 0
Observation : a piece of info we all gather through our 5 senses
Hypotheses: a testable explanation for an observation
Data: info that scientists gather during an experiment
Experiment: a procedure that is designed to test a hypothesis
Conclusion a judgment or decision
Scientific method a series of steps
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a scientist uses 68 grams of CaCo3 to prepare 1.5 liters of solution. what is the molarity of this solution?
victus00 [196]

Answer: 0.4533mol/L

Explanation:

Molar Mass of CaCO3 = 40+12+(16x3) = 40+12+48 = 100g/mol

68g of CaCO3 dissolves in 1.5L of solution.

Xg of CaCO3 will dissolve in 1L i.e

Xg of CaCO3 = 68/1.5 = 45.33g/L

Molarity = Mass conc.(g/L) / molar Mass

Molarity = 45.33/100 = 0.4533mol/L

7 0
4 years ago
the element cesium forms a with the charge fill in the blank 2 . the symbol for this ion is , and the name is fill in the blank
yulyashka [42]

The element cesium forms a  positive ion with the charge +1 . The symbol for this ion is Ce⁺, and the name is cesium ion. The number of electrons in this ion is 54.

<h3>What group does the element cesium belong to in the periodic table?</h3>

Cesium belong to the Group 1A of the periodic table.

Group 1A elements are known as alkali metals.

The alkali metals react with water to form alkalis. They form ions with a positive charge of +1 by the loss of an electron.

In conclusion, cesium is an alkali metals it belongs to group 1A of the periodic table. It forms a positive ion with a charge of +1 by the loss of an electron.

Learn more about alkali metals at: brainly.com/question/25317545

#SPJ1

6 0
2 years ago
Determine whether or not the mixing of each pair of solutions results in a buffer. Show all work!
tia_tia [17]

Answer:

a) Acidic buffer

b) No buffer

c) Acidic buffer

d) Basic buffer

e) Basic buffer

Explanation:

a) 75.0 mL of 0.10 M HF ; 55.0 mL of 0.15 M NaF -Acidic buffer

Mixing of 75.0 mL of 0.10 HF and 55.0 mL of 0.15 mL NaF results in acidic buffer. HF/NaF is a buffer of weak acid and its conjugate base. F- is the conjugate base of acid,HF.

b.) 150.0 mL of 0.10 M HF ; 135.0 mL of 0.175 M HCl-No buffer

Mixing HF and HCl will not results in a buffer. Both are acids, and no conjugate base is present.

c.) 165.0 mL of 0.10 M HF ; 135.0 mL of 0.050 M KOH-Acidic buffer

HF reacts with KOH to form KF. F- is a conjujate base of HF. As volume and concentration of HF is more than KOH, therefore, HF will remain after reaction with KOH. HF/KF will be a buffer of weak acid and its conjugate base.

d.) 125.0 mL of 0.15 M CH3NH2 ; 120.0 mL of 0.25 M CH3NH3Cl -Basic buffer

CH3NH2/CH3NH3+ is a buffer of weak base and its conjugate acid.

e.) 105.0 mL of 0.15 M CH3NH2 ; 95.0 mL of 0.10 M HCl-Basic buffer

CH3NH2 is a weak base and HCl is a strong acid. CH3NH2 reacts with HCl to form its conjugate acid CH3NH3+. Volume and concentration of CH3NH2 is more as compared to HCl and hence, will remain in the soution after reactionf with HCl.

CH3NH3+/CH3NH2 is a buffer of weak base and its conjugate acid.

6 0
4 years ago
How does William Jennings Bryan respond to the criticism that the free and unlimited coinage of silver will disrupt ""business i
kifflom [539]

Answer:

He responded by saying their business definition was far too narrow.

Explanation:

Williams Bryan relates the battle for free silver with the revolution in the United States.

His iconic "Cross of Gold" address ignited the Democratic National Convention in 1896 where he begged the american people not to be "crucified on the cross of gold." He was said this because of the Republicans plan to introduce a firm gold standard and abolish silver coinage.

3 0
3 years ago
Which of the following elements could replace copper in a single replacement reaction?
Likurg_2 [28]
I’m thinking it’s gold because lead isn’t with cooper meaning that if u switch lead with cooper it won’t work at all .
7 0
3 years ago
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