Answer:
KOH contains only one K, so a mole of KOH contains one mole of K. How many atoms of K are in 1 mole of KOH? There are 6.022 × 1023 atoms of potassium in every mole of potassium. Since one mole of KOH contains one mole of K, the answer is 6.022×1023 atoms of K.
Explanation:
Answer:
Explanation:
Beryllium especially, but Boron as well both exhibit metallic characteristics.
The outside ring of Beryllium contains 2 electrons. It would have to take on 6 electrons to have a ring of 8. The same statement can be made about Boron (except that it would need 5 electrons to make 8). It is easier for the atom to give up 2 or 3 than than to take on 5 or 6. It would not be easy to have a 5 or 6 minus charge on it.
The concentration of the solution is 8 M
<u><em>calculation</em></u>
<em> </em>Concentrati<em>on = moles/volume in liters</em>
<em> </em><em>step 1: find moles of HF</em>
<em>moles of HF =mass/molar mass</em>
<em>molar mass of HF = 1+ 19 )= 20 g/mol</em>
<em> moles is therefore = 32.0 g/ 20 g/mol= 1.6 moles</em>
<em>Step 2: convert ml to L</em>
<em>volume in liters = 2.0 x 10^2 / 1000 =0.2 l</em>
<em>step 3: find the concentration</em>
<em>concentration = 1.6 mol / 0.2 l = </em><em>8 M</em>
CaO is Calcium Oxide and is Ionic
X * 0.10 mg/mL = 0.50 mg
x = 0.50 mg / 0.10
x = 5.0 mL
hope this helps!
