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Anna35 [415]
3 years ago
9

Pls help me I don’t know what to dooooo

Chemistry
1 answer:
Ivan3 years ago
5 0
Molarity = moles of solute/volume of solution in liters.

The solute here is NaCl, of which we have 46.5 g. To calculate the molarity of an NaCl solution, we need to know the number of moles of NaCl. To convert from grams to moles, we divide the mass by the molar mass of NaCl. The molar mass of NaCl is the sum of the atomic masses of Na and Cl: 23 amu + 35 amu = 58 amu. For our purposes, we can regard amu as equivalent to grams/mole.

(46.5 g)/(58 g/mol) = 0.8017 moles NaCl.

Now that we know both the number of moles of our NaCl solute and the volume of the solution, we can calculate the molarity:

(0.8017 moles NaCl)/(2.2 L) = 0.364 M.
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How many moles are found in a 350.mL solution of 13.5M HNO3
tiny-mole [99]

Answer: Moles are found in a 350.mL solution of 13.5M HNO_{3} are 4.725 mol.

Explanation:

Given: Volume = 350 mL (1 mL = 0.001 L) = 0.350 L

Molarity = 13.5 M

Molarity is the number of moles of a substance present in a liter of solution.

Therefore, moles of HNO_{3} present in the given solution are calculated as follows.

Molarity = \frac{moles}{Volume (in L)}\\13.5 M = \frac{moles}{0.350 L}\\moles = 4.725 mol

Thus, we can conclude that moles found in a 350.mL solution of 13.5M HNO_{3} are 4.725 mol.

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