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2 years ago

Pls help me I don’t know what to dooooo

Chemistry

1 answer:

Ivan2 years ago

5 0

Molarity = moles of solute/volume of solution in liters.

The solute here is NaCl, of which we have 46.5 g. To calculate the molarity of an NaCl solution, we need to know the number of moles of NaCl. To convert from grams to moles, we divide the mass by the molar mass of NaCl. The molar mass of NaCl is the sum of the atomic masses of Na and Cl: 23 amu + 35 amu = 58 amu. For our purposes, we can regard amu as equivalent to grams/mole.

(46.5 g)/(58 g/mol) = 0.8017 moles NaCl.

Now that we know both the number of moles of our NaCl solute and the volume of the solution, we can calculate the molarity:

(0.8017 moles NaCl)/(2.2 L) = 0.364 M.

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Find the fugacity coefficient of a gaseous species of mole fraction 0.4 and fugacity 25 psia in a mixture at a total pressure of

Oksana_A [137]

<u>Answer:</u> The fugacity coefficient of a gaseous species is 1.25

<u>Explanation:</u>

Fugacity coefficient is defined as the ratio of fugacity and the partial pressure of the gas. It is expressed as $\bar{\phi}$

Mathematically,

$\bar{\phi}_i=\frac{\bar{f_i}}{p_i}$

Partial pressure of the gas is expressed as:

$p_i=\chi_iP$

Putting this expression is above equation, we get:

$\bar{\phi}_i=\frac{\bar{f_i}}{\chi_iP}$

where,

$\bar{\phi}_i$ = fugacity coefficient of the gas

$\bar{f_i}$ = fugacity of the gas = 25 psia

$\chi_i$ = mole fraction of the gas = 0.4

P = total pressure = 50 psia

Putting values in above equation, we get:

$\bar{\phi}_i=\frac{25}{0.4\times 50}\\\\\bar{\phi}_i=1.25$

Hence, the fugacity coefficient of a gaseous species is 1.25

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On a hot summer day you and some friends decide you want to cool down your pool. Determine the mass of ice you would need to add

sergeinik [125]

Answer: The mass of ice you would need to add to bring the equilibrium temperature of the system to 300 K is $16.14 \times 10^{4}$ kg.

Explanation:

We know that relation between heat energy and specific heat is as follows.

q = $m \times S \times \Delta T$

As density of water is 1 kg/L and volume is given as 400,000 L. Therefore, mass of water is as follows.

Mass of water = Volume × Density

= $400,000 L \times 1 kg/L$

= 400,000 kg

or, = $400,000 \times 10^{3}$ g (as 1 kg = 1000 g)

Specific heat of water is 4.2 J/gm K. Therefore, change in temperature is as follows.

$\Delta T$ = 305 K - 273 K

= 32 K

Now, putting the given values into the above formula and calculate the heat energy as follows.

q = $m \times S \times \Delta T$

= $400,000 \times 10^{3} \times 4.2 \times 32 K$

= $5376 \times 10^{7}$ J

or, = $5376 \times 10^{4}$ kJ

According to the enthalpy of melting of ice 333 kJ/Kg of energy absorbed by by 1 kg of ice. Hence, mass required to absorb energy of $5376 \times 10^{4}$ kJ is calculated as follows.

Mass = $\frac{5376 \times 10^{4} kJ}{333 kJ/Kg} \times 1 kg$

= $16.14 \times 10^{4}$ kg

Thus, we can conclude that the mass of ice you would need to add to bring the equilibrium temperature of the system to 300 K is $16.14 \times 10^{4}$ kg.

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