B. compound
source is Glencoe Science book grade 7.
Also I just happening to be learning about this at school
0.06105 moles is the number of moles of water lost.
<h3>What is molar mass?</h3>
Molar mass is defined as the mass in grams of one mole of a substance.
Given data:
Mass of water = 1.1g
Molar mass water = 18.016 g/mol
Moles of water =?
These quantities are related by the following equation;
Moles = 
Substituting the values of the quantities and solving for moles, we have;
Moles = 
= 0.06105 moles.
Hence, the 0.06105 moles is the number of moles of water lost.
Learn more about molar mass here:
brainly.com/question/12127540
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The fourth option on Edgen, "two alcohol functional groups". You're welcome :)
Answer:
A - Increase (R), Decrease (P), Decrease(q), Triple both (Q) and (R)
B - Increase(P), Increase(q), Decrease (R)
C - Triple (P) and reduce (q) to one third
Explanation:
<em>According to Le Chatelier principle, when a system is in equilibrium and one of the constraints that affect the rate of reaction is applied, the equilibrium will shift so as to annul the effects of the constraint.</em>
P and Q are reactants, an increase in either or both without an equally measurable increase in R (a product) will shift the equilibrium to the right. Also, any decrease in R without a corresponding decrease in either or both of P and Q will shift the equilibrium to the right. Hence, Increase(P), Increase(q), and Decrease (R) will shift the equilibrium to the right.
In the same vein, any increase in R without a corresponding increase in P and Q will shift the equilibrium to the left. The same goes for any decrease in either or both of P and Q without a counter-decrease in R will shift the equilibrium to the left. Hence, Increase (R), Decrease (P), Decrease(q), and Triple both (Q) and (R) will shift the equilibrium to the left.
Any increase or decrease in P with a commensurable decrease or increase in Q (or vice versa) with R remaining constant will create no shift in the equilibrium. Hence, Triple (P) and reduce (q) to one third will create no shift in the equilibrium.
