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Tju [1.3M]
2 years ago
5

What mass, in grams, of sodium sulfate is needed to make 230.5 g of a 3.5 % (m/m) aqueous solution of sodium sulfate?

Chemistry
1 answer:
andreev551 [17]2 years ago
7 0

The percent concentration of a solution can be calculated from; mass of solute /mass of solution * 100. The mass of the solute here is 8.1 g.

<h3>What is concentration?</h3>

The term concentration refers to the amount of solute presnt in a solution. There are many ways of expressing concentration such as molarity, molality and percentage.

Here;

mass of solution = 230.5 g

Percent of solute =  3.5 %

3.5 = x/ 230.5 * 100

3.5 = 100x/230.5

230.5(3.5) = 100x

x = 230.5(3.5) /100

x = 8.1 g

Learn more about percent concentration: brainly.com/question/202460?

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The yogurt bacteria are usually Gram-positive, which means the Gram staining process dyes them ________.
ale4655 [162]

Answer:

The staining process will dye them purple (option C)

Explanation:

Gram staining is a method of staining used to distinguish and classify bacterial species into two large groups. Those 2 groups are called Gram- positive and gram - negative groups.

This staining is based on the composition of their cell wall. Gram staining uses crystal violet to stain cell walls, iodine as a mordant, and a fuchsin or safranin counterstain to mark all bacteria.

⇒ Gram- positive bacteria are called gram - positive because they will give a positive result. This according to their cell wand. Their cell wall is typically rich with peptidoglycan and lacks the secondary membrane and lipopolysaccharide layer found in Gram-negative bacteria

Gram- positive bacteria take up the crystal violet stain used in the test, and then appear to be purple-coloured.

⇒ Gram- negative bacteria are called gram - negative because they will give a negative gram result.

Because of the presence of higher lipid content, after the alcohol-treatment, the porosity of the cell wall increases, hence the CVI complex (crystal violet – iodine) can pass through. Thus, the primary stain (crystal violet) is not retained. Gram negative bacteria will appear red or pink.

Yogurt is produced using a culture of Lactobacillus delbrueckii subsp. bulgaricus and Streptococcus thermophilus bacteria. (In addition, other lactobacilli and bifidobacteria). All of those bacteria are gram-positive, what means they will appear <u>purple.</u>

8 0
4 years ago
A. what is atmospheric pressure?
Vanyuwa [196]

Answer:

<em>What is atmospheric pressure? -------> Atmospheric pressure is a force in an area pushed against a surface by the weight of the atmosphere of Earth, a layer of air.</em>

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<em>What is the value of atmospheric pressure at sea level, in newtons per square centimeter? -------> Atmospheric pressure at sea level is about 10 N/cm2 or 100 kPa or about 10 m of water or about 760 mm of mercury, but varies with the weather, and of course altitude.</em>

<em>I hope this helps and have a great day!</em>

Explanation:

6 0
3 years ago
In the laboratory you dilute 2.49 ml of a concentrated 6.00 m hydrochloric acid solution to a total volume of 50.0 ml. what is t
Marizza181 [45]
Equation: M1V1 = M2V2

Where M = concentration & V = volume

Step 1: Write down what is given and what you are trying to find

Given: M1 = 6.00M, V1 = 2.49mL, and V2 = 50.0mL
Find: M2

Step 2: Plug in the values into the equation

M1V1 = M2V2
(6.00M)(2.49mL) = (M2)(50.0mL)

Step 3: Isolate the variable (Divide both sides by 50.0mL so M2 is by itself)

(6.00M)(2.49mL) / (50.0mL) = M2

Answer: M2 = 0.30M 
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4 0
3 years ago
How many L of 3.0 M H2SO4 solution can be prepared by using 100.0 mL OF 18 M H2SO4?
max2010maxim [7]

Answer: A volume of 600 mL of 3.0 M H_{2}SO_{4} solution can be prepared by using 100.0 mL OF 18 M H_{2}SO_{4}.

Explanation:

Given: V_{1} = ?,        M_{1} = 3.0 M\\

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Formula used to calculate the volume is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\3.0 M \times V_{1} = 18 M \times 100.0 mL\\V_{1} = \frac{18 M \times 100.0 mL}{3.0M}\\= 600 mL

Thus, we can conclude that a volume of 600 mL of 3.0 M H_{2}SO_{4} solution can be prepared by using 100.0 mL OF 18 M H_{2}SO_{4}.

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How many orbitals are in the 5th energy level?
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Answer:7

Explanation:

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