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Tju [1.3M]
1 year ago
5

What mass, in grams, of sodium sulfate is needed to make 230.5 g of a 3.5 % (m/m) aqueous solution of sodium sulfate?

Chemistry
1 answer:
andreev551 [17]1 year ago
7 0

The percent concentration of a solution can be calculated from; mass of solute /mass of solution * 100. The mass of the solute here is 8.1 g.

<h3>What is concentration?</h3>

The term concentration refers to the amount of solute presnt in a solution. There are many ways of expressing concentration such as molarity, molality and percentage.

Here;

mass of solution = 230.5 g

Percent of solute =  3.5 %

3.5 = x/ 230.5 * 100

3.5 = 100x/230.5

230.5(3.5) = 100x

x = 230.5(3.5) /100

x = 8.1 g

Learn more about percent concentration: brainly.com/question/202460?

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What substance would you add to KF(aq) to form a buffer solution? View Available Hint(s) What substance would you add to to form
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<h3>Answer</h3>

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<h3>Explanation</h3>

A buffer solution contains <em>a weak acid</em> and<em> its conjugate base</em>. The two species shall have a similar concentration in the solution. It's also possible for <em>a weak base</em> and <em>its conjugate acid</em> to form a buffer solution.

The KF solution already contains large number of \text{F}^{-} ions. The objective is to thus find its conjugate acid or base.

\text{F}^{-} contains no proton \text{H}^{+} and is unlikely to be a conjugate acid. Assuming that \text{F}^{-} is a conjugate base. Adding one proton to \text{F}^{-} would produce its conjugate acid.

\text{H}^{+} \; (aq) + \text{F}^{-} \; (aq) \rightleftharpoons \text{HF}\; (aq)

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