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3 years ago

If y-2 and 2y-1 are the factors of ky^2 + 5y+r then

1 answer:

8 0

The standard form Ax^2 + Bx + C =0 A = k, B = 5, C =r From the factors, the roots are 2, ½ The sum of roots = (2 + ½) =-5/2 Which is also equal to –B/A, -5/k Therefore k = 2 The product of roots = 2(1/2) = 1 Which is also equal to C/A, C/2 Therefore C = 2

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3 years ago

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Nikitich [7]

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Step-by-step explanation:

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2 years ago

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stira [4]

Answer:

$\boxed{4 \sqrt[8]{ {d}^{3} } }$

Step-by-step explanation:

$= > 4 {d}^{ \frac{3}{8} } \\ \\ = > 4({d}^{3 \times \frac{1}{8} }) \\ \\ = > 4( {d}^{3} \times {d}^{ \frac{1}{8} } ) \\ \\ = > 4( {d}^{3} \times \sqrt[8]{d} ) \\ \\ = > 4 \sqrt[8]{ {d}^{3} }$

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