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1 year ago

X+10=1/3(5x+10) How do you solve this equation?

Mathematics

2 answers:

lesantik [10]1 year ago

8 0

Answer:

x = 10

Step-by-step explanation:

x + 10 = 1/3(5x + 10)
x + 10 = 5/3x + 10/3
3x + 30 = 5x + 10
20 = 2x
10 = x

Nikitich [7]1 year ago

3 0

Answer:

x = 10

Step-by-step explanation:

First, subtract 10 from both sides

Next, Simplify

Then, subtract 5/3x from both sides

After, simplify

Lastly, multiply both sides by 3

Then finally simplify for your final answer of x = 10

Hope this helps! :)

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Answer:

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tep-by-step explanation:

In order to find the integral:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx$

we can do the following substitution:

Let's call

$u=(x^3-x^2+x)$

Then

$du = (3x^2-2x+1) dx$

which allows us to do convert the original integral into a much simpler one of easy solution:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \int\ {u^7 \, du = \frac{1}{8} \,u^8 +C$

Therefore, our integral written in terms of "x" would be:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C$

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2 years ago

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Step-by-step explanation:

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Step-by-step explanation:

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