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yarga [219]
3 years ago
9

tuckers score in a video game was changed by -75 points because he missed some targets. he got -15 for each missed target. how m

any targets did he miss
Mathematics
1 answer:
Cerrena [4.2K]3 years ago
8 0
He missed 5 targets because if you multiply 15 by 5 you get 75
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Each morning papa noted the birds feeding on his birdfedder . So far this month he had seen 59 blue jays ,68 black crows , 12 re
Oduvanchick [21]
To solve this question, you need to first look at the total amount of birds and then at the percentage of the blue jays that fed on the bird feeder out of all the other birds.

To calculate the total you add them all together:
59+68+12+1 = 140 birds 

Then the percentages of the blue jays that fed on his bird feeder are:
59/140 *100 = 42.143%

You want to see how many blue jays we can expect to see out of 300 birds. 
So you divide 300 by 100 to see what 1% is = 3 birds 

Then you multiply this amount (1% = 3 birds) by 42.134% which is the percentage of blue jays we can expect to see out of the 300 birds. 
3*42.134 = 126.43 

You round this off to 126 because you cant expect to see half a bird. Even if the answer had been 126.9, you would have rounded it of to 126 because no matter how close it is to the next whole number; you either have a whole bird or you don't.

Final Answer = 126
5 0
3 years ago
Find the measure indicated. Assume that the lines which appear to be tangent are tangent. PART 3
ludmilkaskok [199]

I'll do problems 13 and 14 to get you started.

=====================================================

Problem 13

<h3>Answer:  32 degrees</h3>

-----------------------

Explanation:

Refer to the diagram below for problem 13. Since BD is a tangent of the circle, this means angle ABD is 90 degrees, and furthermore x+y = 90. This solves to y = 90-x.

If we focus on triangle ABC, then we can add the interior angles and set the sum equal to 180

A+B+C = 180

z+y+y = 180

z+2y = 180

z+2(90-x) = 180 .... plug in y = 90-x

z+180-2x = 180

z-2x = 180-180

z-2x = 0

z = 2x

We'll use this later.

Now move onto triangle ABD. This is a right triangle due to angle ABD being 90 degrees. The acute angles z and 26 are complementary, meaning they add to 90. So,

z+26 = 90

z = 90-26

z = 64

Now plug this into z = 2x and solve for x

z = 2x

64 = 2x

2x = 64

x = 64/2

x = 32

=====================================================

Problem 14

<h3>Answer: 31 degrees</h3>

-----------------------

Explanation:

Refer to the image shown below for problem 14. Like before, I've added various labels to it to help find the angle we're after (the red angle x).

Note how I've drawn a dashed line from point A to point D. This splits up quadrilateral ABCD into two triangles ABD and ACD. These triangles can be shown to be congruent using the HL (hypotenuse leg) theorem.

The congruent triangles also implies that angle DBC and angle BCD are the same measure (both are shown in green as the variable y).

Focus on triangle BCD. It has interior angles of: y, y and 62. Add them up, set the sum equal to 180.

y+y+62 = 180

2y+62 = 180

2y = 180-62

2y = 118

y = 118/2

y = 59

As the image attachment mentions, the angles x and y add to 90 degrees. This is because angle ABD is 90 degrees, due to segment BD being tangent to the circle. So x+y = 90 leads to x = 90-y, and therefore,

x = 90-y

x = 90-59

x = 31

Side note: it is not a coincidence that we ended up with half of the value of 62.

3 0
3 years ago
HELPPP
Mazyrski [523]

Answer:

Hello,

Step-by-step explanation:

y-intercept: x=0 ,f(0)=-10

x^3-8x^2+17x-10\\\\=x^3-5x^2-3x^2+15x+2x-10\\\\=x^2(x-5)-3x(x-5)+2(x-5)\\\\=(x-5)(x^2-3x+2)\\\\=(x-5)(x^2-x-2x+2)\\\\=(x-5)(x(x-1)-2(x-1))\\\\=(x-5)(x-1)(x-2)\\

x-intercepts are: 5,1,2.

6 0
2 years ago
8 - 4y + (-2y) + 5 <br><br><br> What is this answer please tell me
Irina-Kira [14]

Answer:

<em>13 - 6y </em>

Step-by-step explanation:

8 - 4y + (-2y) + 5 = <em>13 - 6y</em>

8 0
2 years ago
Read 2 more answers
Reduce then calculate 7/8 x 4/15 x 3/7 = ? <br><br> Can you help?
Zepler [3.9K]

since this is a multiplication, all the numerators are just factors of the product numerator and all denominators are just factors of the product denominator, so we can simply reorder them some, without changing the product.


\bf \cfrac{7}{8}\times \cfrac{4}{15}\times \cfrac{3}{7}\implies \cfrac{7}{7}\times \cfrac{4}{8}\times \cfrac{3}{15}\implies \cfrac{1}{1}\times \cfrac{1}{2}\times \cfrac{1}{5}\implies \cfrac{1\cdot 1\cdot 1}{1\cdot 2\cdot 5}\implies \cfrac{1}{10}

8 0
3 years ago
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