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lisabon 2012 [21]
3 years ago
14

What are the origins of the word fossil

Chemistry
1 answer:
grin007 [14]3 years ago
6 0
The origins of the word fossil are French and Latin
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Contrast (Compare) the Sun's gravitational pull on Earth when Earth is
77julia77 [94]

Answer:

gravity equation.

Explanation:

use this gravity equation

F= G(m1*m2/d²)

3 0
3 years ago
Which part of an investigation is only found in an experimental investigation?
pantera1 [17]

Answer:

The correct answer is control group.

Explanation:

A group used in a study or in an experiment, which does not get treatment by the scientists and is used as a foundation to determine the functions of the other tested subjects is known as the control group. The control group is only found in an experimental investigation.  

The group in an experiment, which gets the variable being examined is known as an experimental group. The comparison of an experimental group is done with a control group in order to find the answers in an experiment.  

3 0
3 years ago
What contains elements with similar properties in the periodic table?
Nataly [62]
A) a column

example: earth alkaline metals
6 0
3 years ago
Read 2 more answers
The structure of a water molecule (H20) can be written as H-O-H, with each dash representing a chemical bond.
svet-max [94.6K]

Answer:

oxygen shows 2 bonds with hydrogen

8 0
3 years ago
The air in a 2 L balloon at 0.998 atm and 34.0 °C. What will be its pressure if it is brought to a higher altitude where it now
Phantasy [73]

Answer: 0.529 atm

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.998 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 2 L

V_2 = final volume of gas = 3.5 L

T_1 = initial temperature of gas = 34.0^oC=273+34.0=307.0K

T_2 = final temperature of gas = 12.0^oC=273+12.0=285.0K

Now put all the given values in the above equation, we get:

\frac{0.998\times 2}{307.0K}=\frac{P_2\times 3.5}{285.0K}

P_2=0.529atm

Thus the pressure if it is brought to a higher altitude where it now occupies 3.5 L and is at 12.0 °C is 0.529 atm

4 0
4 years ago
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