Question

Examine the reaction equation. CH4 + O2 →H2O + CO2 What coefficients will balance the equation? A) 2, 3, 2, 2 B) 1, 3, 2, 1 C) 1, 2, 2, 1 D) 1, 1, 1, 1

Answer 1

Answer:

$\huge \boxed{\mathrm{C) \ 1, 2,2,1}}$

$\rule[225]{225}{2}$

Explanation:

$\sf CH_4+ O_2 \Rightarrow CO_2 + H_2O$

Balancing the Hydrogen atoms on the right side,

$\sf CH_4+ O_2 \Rightarrow CO_2 +2 H_2O$

Balancing the Oxygen atoms on the left side,

$\sf CH_4+ 2O_2 \Rightarrow CO_2 +2 H_2O$

$\rule[225]{225}{2}$

Answer 2

Answer:

B

Explanation:

CH4 + O2 →H2O + CO2

Left side

C = 1

H = 4

O = 2

Right side

C = 1

H = 2

O = 3

So find common denominator in this case would be 6 O

CH4 + 3O2 →2H2O + CO2

Left side

C = 1

H = 4

O = 6

Right side

C = 1

H = 4

O = 6