Question

Which coordinate pair identifies the center of the circle represented by 4x2 + 4y2 − 16x − 24y + 36 = 0.

Answer 1

Answer:A

Step-by-step explanation:

Answer 2

Answer:

Option A is correct

Coordinate pair identifies the center of the circle is, (2 , 3)

Step-by-step explanation:

the general equation of the circle is given by :

$(x-a)^2+(y-b)^2=r^2$ ; where (a, b) represents the coordinates of the circle  and r is the radius of the circle.

Given : $4x^2+4y^2-16x-24y+36=0$

$4x^2-16x+4y^2-24y+36=0$

Take common 4 from above equation we have:

$4(x^2-4x+y^2-6y+9=0)$

Divide both sides by 4 we get;

$x^2-4x+y^2-6y+9=0$

Add and subtract 4 in above equation:

$x^2-4x+y^2-6y+9+4-4=0$

$x^2-4x+4+y^2-6y+5=0$

Add and subtract 9 in above equation:

$x^2-4x+4+y^2-6y+5+9-9=0$

$x^2-4x+4+y^2-6y+9-4=0$

or

$x^2-4x+2^2+y^2-6y+3^2 = 4$

Using identity: $(a-b)^2 = a^2 - 2ab + b^2$

$(x-2)^2+(y-3)^2 = 2^2$

On comparing with the general equation of the circle we have;

a = 2 , b= 3 and r = 2

Therefore, the coordinate pair identifies the center of the circle is, (2 , 3)