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Lady_Fox [76]
3 years ago
7

Atoms that have a full outer level combine with other atoms. Is this true or false

Chemistry
2 answers:
aev [14]3 years ago
8 0

Answer:

false

Explanation:

some atoms already have a full outer level

Romashka [77]3 years ago
7 0
I believe the answer is false
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HELP DUE MONDAY!!<br> Don’t understand
Katyanochek1 [597]

Answer:

Concept: Chemical Analysis

  1. You need to start by graphing the data and then analyzing it.
  2. We can see that the horse has a distance in meters of 980 at the end of the 10 seconds hence it is the fastest.
  3. The horse line has a linearly representation, while the alternate line has parabolic tendencies towards the end. The steeper line indicates a faster change in time or velocity which results in a greater distance traveled indicating that the horse is faster.
  4. *I have confidence you can graph that*
5 0
2 years ago
How many moles are in 3.24 x 1020 particles of lead? (show work plz)
lesya [120]
<h3>Answer:</h3>

0.000538 mol Pb

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.24 × 10²⁰ particles Pb (lead)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                                  \displaystyle 3.24 \cdot 10^{20} \ particles \ Pb(\frac{1 \ mol \ Pb}{6.022 \cdot 10^{23} \ particles \ Pb})
  2. Multiply/Divide:                                                                                               \displaystyle 0.000538 \ mol \ Pb

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

Our final answer is in 3 sig figs, no need to round.

7 0
3 years ago
Acid formulas usually start with ______________ because they have hydrogen atoms combined with other atoms in their molecules
mina [271]

Answer:

H

Explanation:

Example,

HCl for hydrochloric acid

H2SO4 for sulphuric acid

HNO3 for nitric (v) acid

8 0
3 years ago
The nonvolatile, nonelectrolyte estrogen (estradiol), C18H24O2 (272.40 g/mol), is soluble in chloroform CHCl3.
Artist 52 [7]

<u>Answer:</u> The molarity of solution is 0.274 M and the osmotic pressure of the solution is 6.70 atm

<u>Explanation:</u>

To calculate the molarity of the solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Given mass of estrogen = 13.5 g

Molar mass of estrogen = 272.40 g/mol

Volume of solution = 181 mL

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{13.5\times 1000}{272.40\times 181}\\\\\text{Molarity of solution}=0.274M

Hence, the molarity of solution is 0.274 M

To calculate the osmotic pressure of the solution, we use the equation:

\pi=iMRT

where,

\pi = osmotic pressure of the solution = ?

i = Van't hoff factor = 1 (for non-electrolytes)

M = molarity of solute = 0.274 M

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the solution = 298 K

Putting values in above equation, we get:

\pi=1\times 0.274mol/L\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\\pi=6.70atm

Hence, the osmotic pressure of the solution is 6.70 atm

8 0
3 years ago
How many moles of KCLO4 can be produced with 3.45 moles of NaCl. Assume all other reactants are in excess
ycow [4]
NOTE question is incorrect: The question should be:
<span>How many moles of KCLO4 can be produced with 3.45 moles of KCl. Assume all other reactants are in excess.
.......................................................................................................................

The reaction involving formation of KClO4 is 

NaClO4      +       KCl     </span>→    KClO4       +       NaCl

From above reaction, it can be seen that 1 mole of NaClO4 reacts with 1 mole of KCl to generate 1 mole of KClO4

Thus, if all other reactant are in excess, 3.45 moles of KCl  will react with 3.45 moles of NaClO4 to form 3.45 moles of KClO4.
4 0
3 years ago
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