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Andreas93 [3]
2 years ago
9

There are 2.60 x 1015 short tons of oxygen in the atmosphere ( 1 short ton = 2000 lb). How many metric tons of oxygen are oresen

t (1 metric ton =1000 kg) ?
Chemistry
1 answer:
vichka [17]2 years ago
6 0

<u>Answer:</u> 2.36\times 10^{15} metric tons of oxygen is present.

<u>Explanation:</u>

We are given:

Mass of oxygen in atmosphere = 2.60\times 10^{15}\text{ short tons}

To convert it into metric tons, we use the conversion factors:

1\text{ short ton}=2000lb

And,

1\text{ metric ton}=2204.62lb

Converting short tons into pounds, we get:

\Rightarrow 2.60\times 10^{15}\text{ short tons}\times (\frac{2000lb}{\text{1 short ton}})=5.2\times 10^{18}lb

Now, converting the given mass in pounds to metric tons, we get:

\Rightarrow 5.2\times 10^{18}lb\times (\frac{\text{1 metric ton}}{2204.62lb})=2.36\times 10^{15}\text{metric ton}

Hence, 2.36\times 10^{15} metric tons of oxygen is present.

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3 years ago
Choose the molecule(s) that will only show two signals, with an integration ratio of 2:3, in their 1H NMR spectrum.
mrs_skeptik [129]

The question is missing the molecules in which the integration ratio of 2:3 will be observed. The complete question is given in the attachment.

Answer:

Molecule (a), (c), and (f) will show two peaks with the integration ratio of 2:3 in their 1H NMR spectrum

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In the 1H NMR spectrum, the peak area is dependent on the number of hydrogen in a specific chemical environment. Hence, the ratio of the integration of these signals provides us with the relative number of hydrogen in two peaks. This rationale is used for the assignment of molecules that will give 2:3 integration ratio in the given problem.

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3 years ago
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PV=nRT  

P = 85.0 x 10^3 Pa  

T = 273 + 20 = 293 K  

n = 2.0 moles  

R = 8.314 m3. pa / mol .K  

V = 2.0 x 293 x 8.314 / 85.0x10^3 =  0.195623529 m^3

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Q = mC∆T 

<span>where: </span>
<span>q = heat </span>
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<span>q = (35.0 g)*(0.385 J/g*C)*(45C) = 606 J </span>
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