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Andreas93 [3]
3 years ago
9

There are 2.60 x 1015 short tons of oxygen in the atmosphere ( 1 short ton = 2000 lb). How many metric tons of oxygen are oresen

t (1 metric ton =1000 kg) ?
Chemistry
1 answer:
vichka [17]3 years ago
6 0

<u>Answer:</u> 2.36\times 10^{15} metric tons of oxygen is present.

<u>Explanation:</u>

We are given:

Mass of oxygen in atmosphere = 2.60\times 10^{15}\text{ short tons}

To convert it into metric tons, we use the conversion factors:

1\text{ short ton}=2000lb

And,

1\text{ metric ton}=2204.62lb

Converting short tons into pounds, we get:

\Rightarrow 2.60\times 10^{15}\text{ short tons}\times (\frac{2000lb}{\text{1 short ton}})=5.2\times 10^{18}lb

Now, converting the given mass in pounds to metric tons, we get:

\Rightarrow 5.2\times 10^{18}lb\times (\frac{\text{1 metric ton}}{2204.62lb})=2.36\times 10^{15}\text{metric ton}

Hence, 2.36\times 10^{15} metric tons of oxygen is present.

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Based on the position of the elements in the periodic table, what is the charge of the ions they are most likely to form?
Rainbow [258]

Explanation:

The charge on an ion denotes the amount of electrons lost or gained or even shared by an atom.

An atom will lose, gain or share an equal amount of electrons that will make it stable and achieve an octet and perfect configuration.

This is often synonymous with the component number of electrons in their outermost shell. The valence shell.

For metals on the periodic table, they are always willing to give up electrons due to their large electropositivity.

Metals will give up the number of electrons in their outermost shell to become stable.

Groups 1 and Group 2 will have charges +1 and +2 on them.

For non-metals , they will gain the exact number of electrons that will make them stable.  We must note that half -filled and fully filled orbitals are equally stable.

Elements in groups 6 and 7 are electronegative and will have a charge of -2 and -1 respectively.

For those in groups 3, 4 and 5 they either gain, lose or share commensurate amount of electrons that will make them stable.

Group 8 elements are stable and have no charges.

Generally on the periodic table, metals are to the left and are always positively charged. Non - metals are to the right and are negatively charged.

learn more:

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4 0
3 years ago
How much heat is required to convert 20.0 g of ice at 50.0⁰C to liquid water at 0.0⁰C? The specific heat of ice is 2.06 J/(g∙⁰C)
Alex777 [14]

Answer:

8740 joules are required to convert 20 grams of ice to liquid water.

Explanation:

The amount of heat required (Q), measured in joules, to convert ice at -50.0 ºC to liquid water at 0.0 ºC is the sum of sensible heat associated with ice and latent heat of fussion. That is:

Q = m\cdot [c\cdot (T_{f}-T_{o})+L_{f}] (1)

Where:

m - Mass, measured in grams.

c - Specific heat of ice, measured in joules per gram-degree Celsius.

T_{o}, T_{f} - Temperature, measured in degrees Celsius.

L_{f} - Latent heat of fussion, measured in joules per gram.

If we know that m = 20\,g, c = 2.06\,\frac{J}{g\cdot ^{\circ}C}, T_{f} = 0\,^{\circ}C, T_{o} = -50\,^{\circ}C and L_{f} = 334\,\frac{J}{g }, then the amount of heat is:

Q = (20\,g)\cdot \left\{\left(2.06\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot [0\,^{\circ}C-(-50\,^{\circ}C)]+334\,\frac{J}{g} \right\}

Q = 8740\,J

8740 joules are required to convert 20 grams of ice to liquid water.

3 0
3 years ago
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