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Nastasia [14]
3 years ago
6

As an electron moves in the direction the electric field lines:________.

Physics
2 answers:
Doss [256]3 years ago
3 0

Answer: c. it is moving from high potential to low potential and gaining electric potential energy.  

Explanation: As an electron moves in the direction the electric field lines it is moving from high potential to low potential and gaining electric potential energy.

s344n2d4d5 [400]3 years ago
3 0
C. It is moving from high potential to low potential
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How can one tell if an object can absorb light or not? How about transmit?<br> Thank you!
kondaur [170]

<u>Absorb:</u>
Shine a light with known intensity into the object. 
Measure the intensity of the light that comes out.
Any light that goes in but doesn't come out the other side
   was absorbed by the object.
(Note:  You also need to be aware of any light that bounces back from
the first side without entering the object.  That light is <em><u>reflected</u></em> from it,
and can't be expected to show up at the other side.)

<u>Transmit:</u>
Any light that goes in and DOES come out the other side
   was transmitted by the object.


4 0
3 years ago
10_ south of west is a way measure of the direction between south<br>and west.​
k0ka [10]

Answer:

South west or SW

Explanation:

it's in between south and west

3 0
3 years ago
Una pelota se desliza hacia arriba por una pendiente se halla inicialmente a 6m de la parte más baja de dicha pendiente y tiene
jolli1 [7]

Answer:

a) vprom = - 0.6 [m/s] b) ver explicacion c) vf = 10.8 [m/s]

Explanation:

Para poder solucionar este problema debemos completar el enunciado del problema así como la pregunta, realizando una búsqueda en Internet encontramos el enunciado completo, así como la pregunta.

"Una pelota que se desliza hacia arriba por una pendiente se halla inicialmente a 6 m de la parte más baja de dicha pendiente y tiene una velocidad de 4 m/s. Cinco segundos después se encuentra a 3 m de la parte más baja. Si suponemos una aceleración constante, "

¿cual fue la velocidad media?

¿Cuál es el significado de una velocidad media negativa?

¿Cuáles son la aceleración media y la velocidad final?

Para facilitar esta solución debemos realizar un esquema del movimiento de la pelota en el plano inclinado. En la imagen adjunta se puede ver un esquema del movimiento de la pelota sobre el plano inclinado en los diferentes tiempos mencionados.

<u>¿cual fue la velocidad media?</u>

<u />

La velocidad media se debe calcular utilizando la expresión de velocidad = espacio / tiempo.

v_{prom}=x/t\\v_{prom}=(3-6)/5\\v_{prom}=-0.6 [m/s]

<u>¿Cuál es el significado de una velocidad media negativa? </u>

La velocidad media negativa significa que se dirige hacia abajo en sentido contrario

<u>¿Cuáles son la aceleración media y la velocidad final?</u>

<u />

x=v_{o}*t+0.5*a*t^{2} \\-3=(4)*(5)+0.5*a*(5)^2\\a=1.36[m/s^2]\\\\Velocity\\v_{f}=v_{o}+a*t = 4+(1.36*5)\\v_{f}=10.8[m/s]

6 0
3 years ago
Forces are measured in Newtons (N). Why are forces considered to be vectors?
prohojiy [21]

Answer:

A force has both magnitude and direction, therefore: Force is a vector quantity; its units are newtons, N. Forces can cause motion; alternatively forces can act to keep (an) object(s) at rest. ... Consider two forces of magnitudes 5 N and 7 N acting on a particle, with an angle of 90◦ between them.

Explanation:

from google

8 0
3 years ago
A motorist drives south at 24.0 m/s for 3.00 min, then turns west and travels at 25.0 m/s for 2.20 min, and finally travels nort
grigory [225]

Answer:

magnitude m = 5440.26 M

average speed is = 25.05 m/s

average velocity = 14.62 m/s

Explanation:

given data

speed v1 = 24 m/s

time t1 = 3 min = 180 s

speed v2 = 25 m/s

time t2 = 2.2 min = 132 s

speed v3 = 30 m/s

time t3 = 1 min = 60 s

total time = 6.2 min = 372 s

to find out

displacement in m  and average speed and  average velocity

solution

so we find here displacement

displacement = vt    .............1

so

displacement 1 = 24 × 180 =  4220 m south = -4220 j   ..........2

displacement 2 = 25 × 132 = 3300 m west = -3300 i     ...........3

distance 3 = 30 × 60 =  1800 m

displacement   = 1800 cos45 -i + 1800 cos45 j

displacement   = -1272.79 i + 1272.79 j                             .............4

so total displacement D =  equation 2 + equation 3 + equation 4

total displacement D =  -4220 j -3300 i -1272.79 i + 1272.79 j

total displacement D =  -2947.21 j - 4572.79 i

so magnitude m = √(-2947.21)² + (-4572.79)² )

so magnitude m = 5440.26 M

and

average speed is = total distance / time

average speed is = (4220 + 3300+ 1800 ) / 372

average speed is = 25.05 m/s

and

average velocity = total displacement / time

average velocity = 5440.26 / 372

average velocity = 14.62 m/s

7 0
4 years ago
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