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AnnZ [28]
3 years ago
15

If someone lost 20 pounds of fat on a diet, where did the fat go?

Physics
1 answer:
Nana76 [90]3 years ago
7 0
Well usually when you go on a diet, you don't really want gain weight, when you lose 20 pounds on a diet to 20 pounds that you lost got used as energy for your body, if you eat healthy then you can expect to see weight loss.
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What is a normal force?
Flauer [41]
Is the component perpendicular to the surface on contact  of the  contact force  <span />
3 0
4 years ago
You have three identical metallic spheres, A, B and C, fixed to isolating pedestals. They all start off uncharged. You then char
kaheart [24]

Answer:

Charge on B is 12 uC.

Explanation:

Initial charge on A = 32 uC

Initial charge on B and C = 0

Now A touches to B, so the charge on A and B both is

q = (32 + 0) / 2 = 16 uC

Now A touches to C, so the charge on A and C both is

q' = (16 + 0) / 2 = 8 uC

Now again A touches to B so the charge on B is

q''= (8 + 16) / 2 = 12 uC  

7 0
3 years ago
What must the charge (sign and magnitude) of a particle of mass 1.41 gg be for it to remain stationary when placed in a downward
Yuri [45]

Answer:

q = 2.067 \times 10^{-5}\ C

Explanation:

Given,

mass = 1.41 g = 0.00141 Kg

Electric field,E = 670 N/C.

We know,

Force in charge due to Electric field.

F = E q

And also we know

F = m g

Equating both the equation of motion

m g = E q

q =\dfrac{mg}{E}

q =\dfrac{0.00141 \times 9.81}{670}

q = 2.067 \times 10^{-5}\ C

Charge of the particle is equal to q = 2.067 \times 10^{-5}\ C

6 0
4 years ago
If Q = 16 nC, a = 3.0 m, and b = 4.0 m, what is the magnitude of the electric field at point P?
Lynna [10]
In BPC

tan\theta =a/b = 3/4

\theta = tan^-1(0.75)

\theta = 36.87 deg

BP = sqrt(a^2 + b^2) = sqrt((3)^2 + (4)^2) = 5 m

Eb = k Q/BP^2 = (9 x 10^9) (16 x 10^-9)/5^2 = 5.76 N/C

Ea = k Q/AP^2 = (9 x 10^9) (16 x 10^-9)/4^2 = 9 N/C

Ec = k Q/CP^2 = (9 x 10^9) (16 x 10^-9)/3^2 = 16 N/C

Net electric field along X-direction is given as

Ex = Ea + Eb Cos36.87 = (9) + (5.76) Cos36.87 = 13.6 N/C

Net electric field along X-direction is given as

Ey = Ec + Eb Sin36.87 = (16) + (5.76) Sin36.87 = 19.5 N/C

Net electric field is given as

E = sqrt(Ex^2 + Ey^2) = sqrt((13.6)^2 + (19.5)^2) = 23.8 N/C
8 0
3 years ago
The extraction of oil from oil shales can be detrimental to the environment mainly because this process requires large amounts o
zheka24 [161]
I believe the correct answer would be A. The extraction of oil shale is detrimental to the environment mainly because the process of extraction requires large amounts of land. Lands are being excavated in order to locate areas which contains the oil. This is not good since it affects ecosystems and destroy habitats.
5 0
4 years ago
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