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photoshop1234 [79]
3 years ago
11

How does a toaster oven use micro waves

Physics
1 answer:
vekshin13 years ago
5 0
It uses microwaves as little heatwaves and uses them to heat the food
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Plz and ty ... free points, be nice
harkovskaia [24]

Answer:

Thank you!

Explanation:

5 0
2 years ago
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A magnet falls through a loop of wire with the south pole entering first. After it has fallen all the way through the wire loop
Alisiya [41]

Answer:

The induced current direction as viewed is clockwise

Explanation:

Lenz's Law states that the induced e. m. f. causes current to be driven in the loop of wire in such a way as to generate magnetic field that are oppose the magnetic flux change which is the source of the induced current

Therefore, as the magnet approaches the coil with the south pole,  the coil produces current equivalent to the upward movement of the south pole of a permanent magnet through it which according to Flemings Right Hand Rule is clockwise

Therefore;

The direction of the induced current in the loop (as viewed from above, looking down the magnet) is clockwise

5 0
3 years ago
“Persistence, patience, perseverance... When something doesn't work, there is always a solution”
Vanyuwa [196]

Answer:i'm pretty sure it was newton

Explanation:i search it up

8 0
3 years ago
Match the element properties with their descriptions
forsale [732]

1. ability to be pounded into shapes

2. how well a substance flows

3. the mass divided by its volume

4. degree of smoothness

5. ability to dissolve in another substance

6. how shiny a material is

7. ability to be pulled into a wire

4 0
3 years ago
A net force of 1.6×10−15 N acts on an electron over a displacement of 5.0 cm, in the same direction as the net force. (a) What i
Margaret [11]

Explanation:

It is given that,

Net force acting on the electron, F=1.6\times 10^{-15}\ N

Displacement, d = 5 cm = 0.05 m

(a) Let \Delta E is the change in kinetic energy of the electron. It can be calculated using work energy theorem. Mathematically, it is given by :

W=\Delta E

\Delta E=F\times d

\Delta E=1.6\times 10^{-15}\ N\times 0.05\ m

\Delta E=8\times 10^{-17}\ J

(b) Initial speed of the electron, u = 0

Again using the work energy theorem as :

E=\dfrac{1}{2}m(v^2-u^2)

E=\dfrac{1}{2}m(v^2)

v=\sqrt{\dfrac{2E}{m}}

v=\sqrt{\dfrac{2\times 8\times 10^{-17}}{9.1\times 10^{-31}}}    

v=1.32\times 10^7\ m/s

Hence, this is the required solution.

7 0
3 years ago
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