How does a toaster oven use micro waves

A star is rotating at 5.55x10-5 π rad/s, its velocity decelerates at a constant rate of 0.5x10-9 π rad/s2.?

Basile [38]

<h2>The current rotational period of that star is 10.01 hours.</h2>

Explanation:

Given that,

Initial angular velocity of the star, $\omega=5.55\times 10^{-5}\pi \ rad/s$

It decelerates, final angular speed, $\omega_f=0$

Deceleration, $\alpha =-0.5\times 10^{-9}\pi \ rad/s^2$

It is not required to use the rotational kinematics formula. The angular velocity in terms of time period is given by :

$\omega=\dfrac{2\pi}{T}$

T is current rotational period of that star

$T=\dfrac{2\pi}{\omega}$

$T=\dfrac{2\pi}{5.55\times 10^{-5}\pi \ rad/s}$

T = 36036.03 second

or

1 hour = 3600 seconds

So, T = 10.01 hours

So, the current rotational period of that star is 10.01 hours. Hence, this is the required solution. Hence, this is the required solution.

4 0

3 years ago

You ride on an elevator that is moving with constant upward acceleration while standing on a bathroom scale. the reading on the

Blababa [14]

The reading on the scale is greater than your actual weight.

4 0

4 years ago

You have two identical beakers A and B. Each beaker is filled with water to the same height. Beaker B has a rock floating at the

gregori [183]

Answer:

a) if we assume that the water does not spill, Beaker B weighs more than beaker S, or which in this case Beaker A weighs more

b) If it is spilled in water the weight of the two beakers is the same

Explanation:

The beaker weight is

beaker A

W_total = W_ empty + W_water

Beaker B

W_total = W_ empty + W_water + W_roca

a) if we assume that the water does not spill, Beaker B weighs more than beaker S, or which in this case Beaker A weighs more

b) If it is spilled in water, the weight of the two beakers is the same because the amount of liquid spilled and equal to the weight of the stone, therefore the two beakers weigh the same

4 0

3 years ago

A cylindrical capacitor has an inner conductor of radius 2.7 mmmm and an outer conductor of radius 3.1 mmmm. The two conductors

Mars2501 [29]

Answer:

(A) Capacitance per unit length = $4.02 \times 10^{-10}$

(B) The magnitude of charge on both conductor is $Q = 4.22 \times 10^{-19}$ C and the sign of charge on inner conductor is $+Q$ and the sign on outer conductor is $-Q$