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3 years ago

How to identify lone pairs and bond pairs?

1 answer:

4 0

In a chemical bonding the electrons that are in the outer most orbital are the one's involved in bonding. The aim of bonding is that each of the atoms must have an octet of electons ( but there are exception which do not follow this rule ) in their valence orbital in order to become stable.Atoms can either loses, gain or share electrons in order to reach this desired state. In a case where they share, they might share all their valence electrons either with the same or different atoms or a certain number of their electron which will end up with them having eight electrons in their valence orbital. Once the atoms have bonded, the remaining electrons that are not shared between the atoms are called the unshared elctron pair and the electrons that are shared and involved in forming bonds are called the shared electron pair. the unshared electron pair can be shared with another atom that has lost it's electrons, this pair is then called a lone pair.

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Which structure is part of the central nervous system?

Oxana [17]

The spinal cord is part of the central nervous system

4 0

3 years ago

Which of the following is an acid-base neutralization reaction?

ZanzabumX [31]

Answer:

Explanation:

Answer: D

STRONG ACIDS:

HBr

HCl

HNO3

HClO4

H2SO4

8 0

3 years ago

Oxalic acid can remove rust (Fe2O3) caused by bathtub rings according to the reaction Fe2O3(s) - 6H2C2O4(aq) rightarrow 2Fe(C2O4

Katena32 [7]

Answer: The mass of rust that can be removed is 1.597 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .....(1)

Molarity of oxalic acid solution = 0.1255 M

Volume of solution = $6.00\times 10^2mL$ = 600 mL = 0.600 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$0.100M=\frac{\text{Moles of oxalic acid}}{0.600L}\\\\\text{Moles of oxalic acid}=(0.100mol/L\times 0.600L)=0.06mol$

For the given chemical reaction:

$Fe_2O_3(s)+6H_2C_2O_4(aq.)\rightarrow 2Fe(C_2O_4)_3^{3-}(aq.)+3H_2O(l)+6H^+(aq.)$

By Stoichiometry of the reaction:

6 moles of oxalic acid reacts with 1 mole of ferric oxide (rust)

So, 0.06 moles of oxalic acid will react with = $\frac{1}{6}\times 0.06=0.01mol$ of ferric oxide (rust)

To calculate the mass of rust for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of rust (ferric oxide) = 159.7 g/mol

Moles of rust = 0.01 moles

Putting values in above equation, we get:

$0.01mol=\frac{\text{Mass of rust}}{159.7g/mol}\\\\\text{Mass of rust}=(0.01mol\times 159.7g/mol)=1.597g$

Hence, the mass of rust that can be removed is 1.597 grams

5 0

3 years ago

A chemist dissolves 716.mg of pure potassium hydroxide in enough water to make up 130.mL of solution. Calculate the pH of the so

Natasha_Volkova [10]

Answer: The pH of the solution is 13.0

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Given mass of KOH = 716. mg = 0.716 g (Conversion factor: 1 g = 1000 mg)

Molar mass of KOH = 56 g/mol

Volume of solution = 130 mL

Putting values in above equation, we get:

$\text{Molarity of solution}=\frac{0.716\times 1000}{56g/mol\times 130}\\\\\text{Molarity of solution}=0.098M$

1 mole of KOH produces 1 mole of hydroxide ions and 1 mole of potassium ions

To calculate hydroxide ion concentration of the solution, we use the equation:

$pOH=-\log[OH^-]$

We are given:

[tex[[OH^-]=0.098M[/tex]

Putting values in above equation, we get:

$pOH=-\log(0.098)\\\\pOH=1.00$

To calculate the pH of the solution, we use the equation:

pOH + pH = 14

So, pH = 14 - 1.00 = 13.0

Hence, the pH of the solution is 13.0

4 0

3 years ago

In a 0.25 M solution of HA (a weak acid), 1.0 % if the HA is ionised.

aniked [119]

Answer:

dunno

Explanation:

4 0

3 years ago