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Sloan [31]
3 years ago
7

(a) When we rub a plastic rod witha piece of fur, --------------transfer from ----------------to the ------------. In the result

charging fur with ------------charge and plastic rod with-------------charge.
Physics
1 answer:
jolli1 [7]3 years ago
6 0

Answer:

Explanation:

When the two dissimilar bodies rubbed together, they the both of the bodies becomes charged. One of the body gets positive charge and the other body gets negative charge.

the positively charged body loses some electrons and the negatively charged body gains some electrons.

According to the properties of charge when the plastic rod is rubbed with the fur, the plastic rod has a tendency to get the negative charge and the fur has a tendency to get positive charge.

So,

When we rub a plastic rod with a piece of fur, electrons--------------transfer from fur----------------to the -------plastic-----. In the result charging fur with -positive-----------charge and plastic rod with-----negative--------charge.

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E(t)=\sum{Voltage \ Drop}\\\\L\frac{d^2q}{dt^2}+R\frac{dq}{dt}+\frac{1}{C}q=E(t)\\\\\\\frac{d^2q}{dt^2}+5000\frac{dq}{dt}+\frac{1}{0.25\times10^{-6}}q=12\\\\\frac{d^2q}{dt^2}+5000\frac{dq}{dt}+4000000q=12\\\\m^2+5000m+4000000=0\\\\(m+4000)(m+1000)=0\\\\m=-4000  \ or \ m=-1000\\\\q_c=c_1e^{-4000t}+c_2e^{-1000t}

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Q(t)=A,\ Q\prime(t)=0,Q\prime \prime(t)=0\\\\0+0+4000000A=12\\\\A=3\times10^{-6}\\\\Q(t)=3\times10^{-6},\\\\q=q_c+Q(t)\\\\q=c_1e^{-4000t}+c_2e^{-1000t}+3\times10^{-6}\\\\q\prime=-4000c_1e^{-4000t}-1000c_2e^{-1000t}\\q\prime(0)=0\\\\-4000c_1-1000c_2=0\\c_1+c_2+3\times10^{-6}=0\\\\#solving \ simultaneously\\\\c_1=10^{-6},c_2=-4\times10^{-6}\\\\q=10^{-6}e^{-4000t}-4\times10^{-6}e^{-1000t}+3\times10^{-6}\\\\q=10^{-6}(e^{-4000t}-4e^{-1000t}+3)C

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\Large {{ \sf {Question :}}}

<h3>A boy who is riding his bicycle, moves with an initial velocity of 5 m/s. Ten second later, he is moving at 15 m/s. What is his acceleration?</h3>

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