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Sloan [31]
3 years ago
7

(a) When we rub a plastic rod witha piece of fur, --------------transfer from ----------------to the ------------. In the result

charging fur with ------------charge and plastic rod with-------------charge.
Physics
1 answer:
jolli1 [7]3 years ago
6 0

Answer:

Explanation:

When the two dissimilar bodies rubbed together, they the both of the bodies becomes charged. One of the body gets positive charge and the other body gets negative charge.

the positively charged body loses some electrons and the negatively charged body gains some electrons.

According to the properties of charge when the plastic rod is rubbed with the fur, the plastic rod has a tendency to get the negative charge and the fur has a tendency to get positive charge.

So,

When we rub a plastic rod with a piece of fur, electrons--------------transfer from fur----------------to the -------plastic-----. In the result charging fur with -positive-----------charge and plastic rod with-----negative--------charge.

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What is the gravitational force between two identical 5000 kg asteroids whose centers of mass are separated by 100 m?
Alenkinab [10]

Answer: 1.67 x 10^-7N

Explanation:

5 0
3 years ago
Which component of weight is cause for S.H.M of bob simple pendulum
jeka57 [31]

Explanation:

The Simple Pendulum. A simple pendulum is defined to have a point mass, also known as the pendulum bob, which is suspended from a string of length L with negligible mass ((Figure)). Here, the only forces acting on the bob are the force of gravity (i.e., the weight of the bob) and tension from the string.

hope it helps you

6 0
2 years ago
A body of mass 25kg, moving at 3 ms per second on a rough horizontal floor brought to rest after sliding through a distance of 2
erastova [34]
You have to solve this by using the equations of motion:
u=3
v=0
s=2.5
a=?
v^2=u^2+2as
0=9+5s
Giving a=-1.8m/s^2

Then using the equation:
F=ma
F is the frictional force as there is no other force acting and its negative as its in the opposite direction to the direction of motion.

-F=25(-1.8)
F=45N

Then use the formula:
F=uR
Where u is the coefficient of friction, R is the normal force and F is the frictional force.

45=u(25g)
45=u(25*10)

Therefore, the coefficient of friction is 0.18

Hope that helps




5 0
3 years ago
You are at the edge of a diving board that is 9 meters above the water. If you weigh 500 Newtons, what is your potential energy?
Semenov [28]

Answer:

4500 J

Explanation:

First, let's define some equations and derivations.

Our potential energy formula is:

  • \displaystyle U = mgh

Where <em>m </em>is mass (in kg), <em>g</em> is the gravitational constant (in m/s²), and <em>h</em> is height (in m).

We also know that <em>mg</em> is equal to the weight of an object (in N), from Newton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration).

Therefore, we can simply substitute force into the equation:

  • \displaystyle U = Fh

Where <em>F</em> is the force (in N) and <em>h</em> is still height (in m).

Now we can calculate the amount of potential energy in our system, measured in joules.

Substitute in the given variables, F = 500 N and h = 9 m:

  • \displaystyle U = (500 \ N)(9 \ m)

Using simple Pre-Algebra rules, we find that:

  • \displaystyle U = 4500 \ J

This tells us that the we have 4500 joules of potential energy when I am 9 meters above the water on the edge of the diving board.

6 0
3 years ago
Read 2 more answers
A water wheel rotates with a period of 2.26 s. If the water wheel has a radius of l.94 m,
Dafna11 [192]

Answer:

The correct answer is B)

Explanation:

When a wheel rotates without sliding, the straight-line distance covered by the wheel's center-of-mass is exactly equal to the rotational distance covered by a point on the edge of the wheel.  So given that the distances and times are same, the translational speed of the center of the wheel amounts to or becomes the same as the rotational speed of a point on the edge of the wheel.

The formula for calculating the velocity of a point on the edge of the wheel is given as

V_{r} = 2π r / T

Where

π is Pi which mathematically is approximately 3.14159

T is period of time

Vr is Velocity of the point on the edge of the wheel

The answer is left in Meters/Seconds so we will work with our information as is given in the question.

Vr = (2 x 3.14159 x 1.94m)/2.26

Vr = 12.1893692/2.26

Vr = 5.39352619469

Which is approximately 5.39

Cheers!

7 0
2 years ago
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