<span>R² = 12² + 4² - 2*12*4cos45° </span>
<span>R² = 92.12 </span>
<span>R = 9.6 mph ===========> ANSWER </span>
<span>Use law of sines to find bearing </span>
<span>4/sinA = R/sin45° </span>
<span>sinA = 4sin45°/9.6 = 0.2946278...... </span>
<span>A = 17.14° </span>
<span>bearing = North 17.14° West or 342.86°</span>
Answer:
(a) 333.77 J
(b) 237.85 J
(c) 4763.77 J
(d) 4667.85 J
Explanation:
Temperature of source, TH = 314 K
Temperature of A, Tc = 292 K
Temperature of B, Tc' = 298 K
heat taken out, Qc = 4430 J
Let the heat deposited outside is QH and QH' by A and B respectively.

Now

(a) Work done for A
W = QH - QC = 4763.77 - 4430 = 333.77 J
(b) Work done for B
W' = QH' - Qc = 4667.85 - 4430 = 237.85 J
(c) QH = 4763.77 J
(d) QH' = 4667.85 J
Answer:
a. E=1440KJ
b. E=360KJ
c. E=1.8 J
Explanation:
I have the power (Watts) is expressed as Energy (Joules) / Time (seconds), also I have to
so, for the lightbulb

Analogously, for the microwave

Now, I have to express the efficiency as Heat energy / power * 100 so
Done
Wheel chair ramp, slide, and staircase