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lana [24]
3 years ago
12

Why is the fact that earth was molten liquid in its early stages the most important event in history

Physics
1 answer:
trasher [3.6K]3 years ago
3 0

It was important because it tells why the denser material had sunken and the lighter is floating on the surface.

<u>Explanation:</u>

Eventually, after around 500 million years, our young planet's temperature warmed to the liquefying purpose of iron—about 1,538° Celsius (2,800° Fahrenheit). This crucial crossroads in Earth's history is known as the iron fiasco. The iron fiasco permitted more prominent, progressively quick development of Earth's liquid, rough material.

We also know that at one point all the material in the planet was molten because the denser material had sunk and the lighter was floating.

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The height of a cone is increasing at a rate of 10 cm/sec and its radius is decreasing so that its volume remains constant. How
ki77a [65]

Answer:

dr/dt = -2 cm/s.

Explanation:

The volume of a cone is given by:

V=\frac{1}{3} \pi r^{2}h (1)

  • r is the radius
  • h is the height

Let's take the derivative with respect to time in each side of (1).

\frac{dV}{dt}=\frac{1}{3} \pi \frac{d}{dt}(r^{2}h)=\frac{1}{3} \pi \left(2r\frac{dr}{dt}h+r^{2}\frac{dh}{dt} \right) (2)

We know that:

  • dh/dt = 10 cm / s (rate increasing of height)
  • dV/dt = 0 (constant volume means no variation with respect of time)
  • r = 4 cm
  • h = 10 cm

We can calculate how fast is the radius changing using the above information.

0=\frac{1}{3} \pi \left( 2\cdot 4\cdot \frac{dr}{dt} \cdot 10 + 4^{2}\cdot 10)\right  

Therefore dr/dt will be:

\frac{dr}{dt}=-\frac{160}{80}=-2 cm/s

The minus signs means that r is decreasing.

I hope it helps you!

6 0
3 years ago
A feather is dropped on the moon from the height of 1.4m. The acceleration of gravity on the moon is 1.67ms-1. Determine the tim
Zinaida [17]

1.3s

Explanation:

Given parameters:

Height = 1.4m

Gravity on moon = 1.67ms⁻¹

Unknown:

Time for feather to fall = ?

Solution:

To solve this problem, we are going to use one of the motion equation that relates time, gravity and height.

    H = ut + \frac{1}{2} g t^{2}

Sine the body was dropped from rest, initial velocity is zero;

 H = height

  u = initial velocity

  t = time

  g = acceleration due to gravity

since u = 0;

H = \frac{1}{2} g t^{2}

 1.4 = \frac{1}{2} x 1.67 x t²

  t = 1.3s

learn more:

Gravity brainly.com/question/10934170

#learnwithBrainly

8 0
3 years ago
Convert 9.75 millimeters to centimeters.
Alex777 [14]
0.975 is correct, to get the answer you divide the length value by 10.
4 0
3 years ago
Read 2 more answers
A bag of cement weighing 325 N hangs in equilibrium from three wires. Two of the wires make angles of theta1=60.0 degrees and th
Murljashka [212]
The sketch of the system is: two strings, 1 and 2, are attached to the ceiling and to a third string, 3.The third string holds the bag of cement. 

The free body diagram of the weight with the string 3, drives to the tension T3 = weihgt => T3 = 325 N

The other free body diagram is around the joint of the three strings.

In this case, you can do the horizontal forces equilibrium equation as:

T1* cos(60) - T2*cos(40) = 0

And the vertical forces equilibrium equation:

Ti sin(60) + T2 sin(40) = T3 = 325 N

Then you have two equations with two unknown variables, T1 and T2

0.5 T1 - 0.766 T2 = 0

 0.866 T1 + 0.643T2 = 325

When you solve it you get, T1 = 252.8 N and T2 = 165 N

Answer: T1 = 252.8 N, T2 = 165N, and T3 = 325N



 
7 0
3 years ago
In the simulation above, as the projectile travels upward, how does the vertical velocity change? Question 9 options:
enot [183]

Answer:

Vertical velocity decreases.

Explanation:

The motion of the ball is a projectile ball, which consists of two independent motions:

- a horizontal motion, with constant velocity

- a vertical motion, with constant acceleration g=9.8 m/s^2 towards the ground

In the vertical motion, there is a constant acceleration directed downward: this means that the vertical velocity decreases as the ball goes higher. In fact, it decreases following the equation

v(t)=v_0 -gt

And it decreases until the ball reaches its maximum height, then it starts increasing again.

4 0
3 years ago
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