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NeTakaya
4 years ago
14

You run a race with your friend. At first you each have the same kinetic energy, but then you find that she is beating you. When

you increase your speed by 28%, you are running at the same speed she is. If your mass is 86 kg, what is her mass?
Physics
1 answer:
Blizzard [7]4 years ago
3 0

Answer:

52.49 Kg

Explanation:

Let m1 and v1 denote your mass and velocity respectively

Let m2 and v2 denote your friends mass and velocity respectively

Kinetic energy is given by

KE= 0.5mv^{2}  

Since your kinetic energies are the same hence

0.5m1(v1)^{2}=0.5m2(v2)^{2}

m1(v1)^{2}=m2(v2)^{2} and making m2 the subject then  

m2=\frac { m1(v1)^{2}}{(v2)^{2}}

Since v2 is v1+0.28v1=1.28v1

Substituting m1 for 86 Kg

m2=\frac { 86 Kg(v1)^{2}}{(1.28v1)^{2}}= 52.49023\approx 52.49 Kg

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7 0
3 years ago
A car travels along a clear 10.0 km section of motorway in 6.0 minutes. It then drives through 3.0 km of roadwork in 3.0 minutes
Charra [1.4K]
  • 6min=1/10h=0.1h
  • 3min=1/20h=0.05h

\\ \bull\tt\dashrightarrow Avg\:Speed=\dfrac{Total\:Displacement}{Total\:Time}

\\ \bull\tt\dashrightarrow Avg\:Speed=\dfrac{10+3}{0.1+0.05}

\\ \bull\tt\dashrightarrow Avg\:Speed=\dfrac{13}{0.15}

\\ \bull\tt\dashrightarrow Avg\:Speed=86.6km/h

5 0
3 years ago
If you put two identical cars on opposite sides of a large magnet, what happens
FrozenT [24]

Answer:

Depends on what pole it is.

Explanation:

If the poles of the cars and magnets are the same they will repel, if different, attracts.

7 0
3 years ago
Read 2 more answers
The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 6.0 rev/s in 11.0 s. At th
sleet_krkn [62]

Answer

given,

ω₁ = 0 rev/s

ω₂ = 6 rev/s

t = 11 s

Using equation of rotational motion

The angular acceleration is

  ωf - ωi = α t

  11 α = 6 - 0

      = 0.545 rev/s²

The angular displacement

  θ₁= ωi t + (1/2) α t²

  θ₁= 0 + (1/2) (0.545)(11)^2

  θ₁= 33 rev

case 2

ω₁ = 6 rev/s

ω₂ = 0 rev/s

t = 14 s

Using equation of rotational motion

The angular acceleration is

  ωf - ωi = α t

  14 α = 0 - 6

        = - 0.428 rev/s²

The angular displacement

  θ₂= ωi t + (1/2) α t²

  θ₂= 6 x 14 + (1/2) (-0.428)(14)^2

  θ₂= 42 rev

total revolution in 25 s is equal to

θ =  θ₁ +  θ₂

θ =  33 + 42

θ = 75 rev

3 0
3 years ago
If something is traveling at 20 m/s constant velocity, is it in equilibrium? If a projectile is launched at a velocity of 20 m/s
Irina18 [472]

If something is traveling at 20 m/s constant speed AND its direction isn't changing, then its velocity is constant.  Another way to say that is: Its acceleration is zero.  Zero acceleration means zero NET force acting on the object, or a group of BALANCED forces acting on it, also called EQUILIBRIUM.  The required answer is: YES.

If a real projectile is launched, the force of gravity acts on it vertically downward.  There's no upward force acting on it to balance gravity.  Therefore, the forces on the projectile are NOT balanced, there IS a net vertical force on it, and it's NOT in equilibrium.  Too bad.


3 0
3 years ago
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