Answer:
Using lighter material in car construction, improving energy efficiency by enhancing engine design or replacing the engine with more efficient technologies.
Explanation:
Using lighter materials in the car construction, reducing the potential energy required to accelerate and to move the car, as well as energy losses due to rolling friction. There is evidence of such benefits by replacing steel and aluminium parts with components made of composite materials.
Improving the design of internal combustion engines to minimize energy losses and accordingly, improving energy efficiency. A more radical approach is replacing internal combustion engines with electric engines, which offer higher efficiencies. Such conclusions can be easily inferred from model based on Work-Energy Theorem and Principle of Energy Conservation:

A run though an open field during a thunderstorm is the answer
Answer:
The correct answer is from Tech B.
Explanation:
The relay is an electromagnetic device, which is stimulated by a very weak electrical current to open or close a circuit. It functions as a switch controlled by an electrical circuit in which, by means of a coil and an electromagnet, a sequence of one or several contactors is activated that allow to open or close other electrical circuits independent of the one that controls it.
Have a nice day!
Answer:
A)
B)
C)
Explanation:
Given that:
- no. of turns i the coil,

- area of the coil,

- time interval of rotation,

- intensity of magnetic field,

(A)
Initially the coil area is perpendicular to the magnetic field.
So, magnetic flux is given as:
..................................(1)
is the angle between the area vector and the magnetic field lines. Area vector is always perpendicular to the area given. In this case area vector is parallel to the magnetic field.


(B)
In this case the plane area is parallel to the magnetic field i.e. the area vector is perpendicular to the magnetic field.
∴ 
From eq. (1)


(C)
According to the Faraday's Law we have:



(a) The height of the cliff will be 8.26 meters.
(b) The time would it take to reach the ground will be 0.717 sec.
<h3>What is velocity?</h3><h3 />
The change of displacement with respect to time is defined as the velocity. Velocity is a vector quantity. it is a time-based component.
(a) The height of the cliff will be 8.26 meters.
According to Newton's second equation of motion

Hence The height of the cliff will be 8.26 meters.
(b)The time would it take to reach the ground will be 0.717 sec.
We must have the final velocity to find the time so;

According to Newton's third equation of motion ;

Hence the time would it take to reach the ground will be 0.717 sec.
To learn more about the velocity refer to the link ;
brainly.com/question/862972