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Wittaler [7]
3 years ago
7

The distance between two successive maximaof

Physics
1 answer:
denpristay [2]3 years ago
4 0

Answer:

v = 1.224 m/s

Explanation:

given,                          

distance between the two successive maxima = 1.70 m

number of crest = 8          

time = 11 s                            

frequency is equal to number of cycle per secod

f = \dfrac{8}{11}          

f = 0.72\ Hz                

velocity of wave

v = f x λ                

v = 0.72 x 1.70        

v = 1.224 m/s          

Hence, the wave speed is equal to v = 1.224 m/s

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