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Wittaler [7]
4 years ago
7

The distance between two successive maximaof

Physics
1 answer:
denpristay [2]4 years ago
4 0

Answer:

v = 1.224 m/s

Explanation:

given,                          

distance between the two successive maxima = 1.70 m

number of crest = 8          

time = 11 s                            

frequency is equal to number of cycle per secod

f = \dfrac{8}{11}          

f = 0.72\ Hz                

velocity of wave

v = f x λ                

v = 0.72 x 1.70        

v = 1.224 m/s          

Hence, the wave speed is equal to v = 1.224 m/s

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<h3>What are the differences between these types of power?</h3>

Nuclear power plants will last much longer than that of coal-fired stations given that the coal-powered plants rely on a finite natural resource. Nuclear power plants are also much safer and cleaner for the environment <u>if handled and cared for correctly</u>. This is due to the large amounts of greenhouse gasses emitted by coal burning.

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2 years ago
What type of device uses an electromagnet to convert electrical energy into mechanical energy?
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This might be totally wrong cause i have no context as to what this question is referring to but a ceiling fan uses magnets and electricity to rotate
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3 years ago
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A non-reflective coating that has a thickness of 198 nm (n = 1.45) is deposited on top of a substrate of glass (n = 1.50). What
spin [16.1K]

Answer:

The  wavelength is \lambda_ 1 =  574.2 nm

Explanation:

From the question we are told that  

      The  thickness is t =  198 nm  =  198 *10^{-9 }\ m

      The refractive  index of the non-reflective coating is  n_m  =  1.45  

       The  refractive  index of glass is n_g  = 1.50

       

Generally the condition for  destructive  interference is mathematically represented as

            2 *  n_m *  t  *  cos (\theta) =  n  *  \lambda

Where \thata \theta is the angle of refraction which is  0° when the light is strongly transmitted

    and  n is the order maximum interference

        so  

             \lambda = \frac{2 *  n *  t  *  cos (\theta )}{n}

at the point n =  1  

           \lambda _1 = \frac{2 *  1.45  *  198*10^{-9}  *  cos (0 )}{1}

           \lambda_1  = 574.2 *10^{-9}

          \lambda_1  = 574.2 nm

at  n =2  

         \lambda _2  =  \frac{\lambda _1 }{2}

         \lambda _2  =  \frac{574.2*10^{-9} }{2}

         \lambda _2  =  2.87 1 *10^{-9} \ m

         \lambda _2  =  287. 1  nm

Now we know that the wavelength range of visible light is  between

           390 \ nm \to  700 \ nm

   So the wavelength of visible light that is been transmitted is  

          \lambda_ 1 =  574.2 nm

           

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4 years ago
A cardboard box sits on top of a concrete sidewalk where the coefficient of friction between the surfaces is 0.3. The mass of th
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Hope these r correct:
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2 years ago
PLEASE HELP!!!!!!!!!!!
Alexxandr [17]
I am 100% sure its A.
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3 years ago
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