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Semenov [28]
3 years ago
12

Which of the following objects would have the strongest gravitational pull on a third object positioned at an equal distance fro

m both boxes
Box A is 3 times bigger than Box B but Box A weighs 100g & Box B weighs 10,000 g
Physics
1 answer:
3241004551 [841]3 years ago
8 0
I believe Box B will have a greater gravitational pull because the gravitational pull of an object depends on its mass. The more mass an object has, the greater its gravitational pull will become.

For example, we can take planets. Naturally, they are round because once upon a time there was a larger piece of rock that attracted others. But the size of the rock won't matter, it's the weight that matters. If the rock weighed nothing, the other rocks would just rebound upon contact. But if the rock weighed a lot, then things wouldn't so easily rebound and might actually stick to it.
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When a balloon is deflating, why does air leave the balloon?
Gwar [14]

Answer:

<em>When a balloon deflates air moves out of the balloon </em><em>because the pressure inside the balloon is higher than the pressure outside the balloon.</em>

Explanation:

An inflated balloon has a high pressure region on its inside. Gases always move from a region of high pressure to a region of low pressure. When a balloon is inflated its membrane stretches making it even more porous.

The gas molecules inside the balloon easily diffuse out through this membrane. The diffusion rate may differ depending on the type of gas filled inside the balloon and the material of the balloon. For example helium balloon deflates faster than common air balloon.

This is because helium is a light element and can escape easier than gases like nitrogen and oxygen through the porous membrane of the balloon.

6 0
2 years ago
When a voltage difference is applied to a piece of metal wire, a current flows through it. if this metal wire is now replaced wi
Nikitich [7]

The resistance of the cylindrical wire is R=\frac{\rho l}{A}.

Here R is the resistance, l is the length of the wire and A is the area of cross section. Since the wire is cylindrical A=\frac{\pi d^2}{4} .

Comparing two wires,

R_1=\frac{\rho_1 l}{A_1} \\ R_2=\frac{\rho_2 l}{A_2}

Dividing the above 2 equations,

\frac{R_1}{R_2}=\frac{\rho_1 }{\rho_2}  \frac{A_2 }{A_1}  \\ \frac{R_1}{R_2}=\frac{\rho_1 }{\rho_2}  \frac{d_2^2 }{d_1^2}  \\

Since d_2=2d_1

The above ratio is

\frac{R_1}{R_2}=\frac{1.68(10^{-8})  }{1.59(10^{-8}) } (4)\\ \frac{R_1}{R_2}=4.2264

We also have,

\frac{E/R_1}{E/R_2} =\frac{I_1}{I_2} \\ I_2=\frac{R_1}{R_2}I_1 \\ I_2=4.23I_1

The current through the Silver wire will be 4.23 times the current through the original wire.

8 0
2 years ago
What is the guage pressure of an object with a mass of 30 kg and 5ft height?
wariber [46]

Answer: D=pg

Explanation:

?????

8 0
2 years ago
How to calculate the speed using time and distance
-Dominant- [34]

Answer:

speed = distance/time

Explanation:

distance -> s

speed -> v

time -> t

3 0
3 years ago
What is the lowest mass that an object can have and still be a star?
CaHeK987 [17]

Answer:

The lowest mass that an object can have to be considered a star is 0.08 solar masses.    

Explanation:

A star is get when it reaches the necessary temperature in its core to nuclear reaction began.

A Nuclear reaction is the fusion of lighter elements into heavier elements.

In stars there is an equilibrium between two forces, the force of gravity in the inward direction due to its own mass and the radiation pressure in the upward direction as a consequence of the nuclear reaction in its core, which is known as hydrostatic equilibrium.

Therefore, the mass of the star must be enough to the force of gravity act in the inward direction, which leads to the increase in pressure, density and of course temperature in the core, allowing the nuclear reaction to begin.

Hence, the lowest mass that an object can have to be consider a star is 0.08 solar masses.    

5 0
3 years ago
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