Explanation:
The force of the roller-coaster track on the cart at the bottom is given by :
, m is mass of roller coaster
Case 1.
R = 60 m v = 16 m/s

Case 2.
R = 15 m v = 8 m/s

Case 3.
R = 30 m v = 4 m/s

Case 4.
R = 45 m v = 4 m/s

Case 5.
R = 30 m v = 16 m/s

Case 6.
R = 15 m v =12 m/s

Ranking from largest to smallest is given by :
F>E>A=B>C>D
The primary job of a(n) ____
is to increase the power of a modified radio wave.
Answer:
<h2>amplifier</h2>
Explanation:
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Answer:
12.14 cm
Explanation:
mass, m = 15.5 kg
frequency, f = 9.73 Hz
maximum amplitude, A = 14.6 cm
t = 1.25 s
The equation of the simple harmonic motion
y = A Sin ωt
y = A Sin (2 x π x f x t)
put, t = 1.25 s, A = 14.6 cm, f = 9.73 Hz
y = 14.6 Sin ( 2 x 3.14 x 9.73 x 1.25)
y = 14.6 Sin 76.38
y = 12.14 cm
Thus, the displacement of the particle from the equilibrium position is 12.14 cm.
Answer is E
time can be negative.
A is not true because <span>a=<span><span><span>d2</span>x</span><span>d<span>t2</span></span></span>=12 m/<span>s2</span></span>
C: question already said that particle move along x-axis, which is not parabola path.
D: velocity is <span><span><span>dx</span><span>dt</span></span>=12t</span>, therefore velocity changes by 12 m/s and not 9.8 m/s
So we are left with E.
<span>
</span>
Answer:
48 m
Explanation:
Two trains traveling towards one another on a straight track are 300m apart when the engineers on both trains become aware of the impending Collision and hit their brakes. The eastbound train, initially moving at 97.0 km/h Slows down at 3.50ms^2. The westbound train, initially moving at 127 km/h slows down at 4.20 m/s^2.
The eastbound train
First convert km/h to m/s
(97 × 1000)/3600
97000/3600
26.944444 m/s
As the train is decelerating, final velocity V = 0 and acceleration a will be negative. Using third equation of motion
V^2 = U^2 - 2as
O = 26.944^2 - 2 × 3.5 S
726 = 7S
S = 726/7
S1 = 103.7 m
The westbound train
Convert km/h to m/s
(127×1000)/3600
127000/3600
35.2778 m/s
Using third equation of motion
V^2 = U^2 - 2as
0 = 35.2778^2 - 2 × 4.2 × S
1244.52 = 8.4S
S = 1244.52/8.4
S2 = 148.2 m
S1 + S2 = 103.7 + 148.2 = 251.86
The distance between them once they stop will be
300 - 251.86 = 48.14 m
Therefore, the distance between them once they stop is 48 metres approximately.