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The average time that it takes for the car to travel the first 0.25m is 2.23 s
The average time that it takes for the car to travel the first 0.25 m is given by:

The average time to travel just between 0.25 m and 0.50 m is 0.90 s
First of all, we need to calculate the time the car takes in each trial to travel between 0.25 m and 0.50 m:

Then, the average time can be calculated as

Given the time taken to travel the second 0.25 m section, the velocity would be 0.28 m/s
The velocity of the car while travelling the second 0.25 m section is equal to the distance covered (0.25 m) divided by the average time (0.90 s):

Using momentum balance:
The 588 N mother is on the other side of the seesaw, 2.20m away from the pivot
F1 = 588 N
x1 = 2.20 m
Two of her children sat on the other side:
F2 = 256 N
x2 = 2.00 m
F3 = 412 N
x3 = unknown
F1x1 = F2x2 + F3x3
Solve for x3:
588 * 2.2 = 256 * 2 + 412 * x3
x3 = 1.90 meters away from pivot
Answer:
I can't see it good on my phone sorry can't help you