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kiruha [24]
3 years ago
7

What is the relationship among amplitude,crest,and trough?

Physics
1 answer:
Musya8 [376]3 years ago
5 0
These are characteristics of a wave. The amplitude is how high and low the waves go. Crests are high points on the wave, and troughs are low points on the wave.
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Why does the sun appear to rise in the east and set in the west every day?
anygoal [31]

Answer: even heating

Explanation:

the earth rotates

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A4 kg bowling ball begins rolling down a at bowling alloy at 6 m/s . When it strikes the pins, it is estimated to be moving at 5
Paul [167]

Answer:

Energy lost due to friction is 22 J      

Explanation:

Mass of the ball m = 4 kg

Initially velocity of ball v = 6 m/sec

So kinetic energy of the ball KE=\frac{1}{2}mv^2

KE=\frac{1}{2}\times 4\times 6^2=72J

Now due to friction velocity decreases to 5 m/sec

Kinetic energy become

KE=\frac{1}{2}\times 4\times 5^2=50J

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8 0
3 years ago
How do i find stretch? The problem in questioning has already given me the elastic energy and k-value, but I have no idea how to
finlep [7]

Answer:

Stretch can be obtained using the Elastic potential energy formula.

The expression to find the stretch (x) is x=\sqrt{\frac{2\times EPE}{k}}

Explanation:

Given:

Elastic potential energy (EPE) of the spring mass system and the spring constant (k) are given.

To find: Elongation in the spring (x).

We can find the elongation or stretch of the spring using the formula for Elastic Potential Energy (EPE).

The formula to find EPE is given as:

EPE=\frac{1}{2}kx^2

Rewriting the above expression in terms of 'x', we get:

x=\sqrt{\frac{2\times EPE}{k}}

Example:

If EPE = 100 J and spring constant, k = 2 N/m.

Elongation or stretch is given as:

x=\sqrt{\frac{2\times EPE}{k}}\\\\x=\sqrt{\frac{2\times 100}{2}}\\\\x=\sqrt{100}=10\ m

Therefore, the stretch in the spring is 10 m.

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6 0
3 years ago
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ivanzaharov [21]

Answer:

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3 = 0.125g

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3 0
2 years ago
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Answer:

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Explanation:

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