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nevsk [136]
3 years ago
15

2(x-3)=3/4(8x-12) step by step please

Mathematics
1 answer:
Umnica [9.8K]3 years ago
7 0

Answer:

x = \frac{3}{4}

Step-by-step explanation:

2(x-3)=\frac{3}{4} (8x-12)

2x-6 = \frac{3}{4}8x- \frac{3}{4} 12

2x-6 = 6x - 9

-6+9 = 6x - 2x

3 = 4x

x = \frac{3}{4}

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marysya [2.9K]

y=−3x+9 slope of this equation is -3 and y-intercept is 9

Plot the y -intercept first which is 9 and mark the points using the slope which is -3. Join the points. So blue line in the graph is y = -3x+9

y=−x−5 slope of this equation is -1 and y intercept is -5

Plot the y -intercept first which is -5 and mark the points using the slope which is -1 . Join the points. So pink line in the graph is y = -x-5

The intersection point of these two lines gives you the solution.

The coordinates of point of intersection (7,-12)


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3 years ago
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Mason cuts a giant circular cookie into 5 equal pieces. Which statements are true about the angle measures of the pieces?
Jobisdone [24]

Answer:

A statement that is true about the angle measures of the pieces is that the angle measure of each piece is 72°. This is because there are 360° in a full circle, and if each piece is equal, that means that each piece is a fifth of that. Therefore, the angle measure is 360/5= 72°

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2 years ago
If candy cost $5.99 a pound how much would it cost to buy four and a quarter pounds of candy
Degger [83]

Answer:

25.4575

Step-by-step explanation:First since one candy is 5.99 we multiply it by 4 1/4 ponds and then we get $25.4575


7 0
3 years ago
How to solve for y 3y=2x+15
SVEN [57.7K]

Answer:

y = (2x + 15)/3

Step-by-step explanation:

3y = 2x + 15

Divide both sides by 3,

3y/3 = 2x/3 + 15/3

Simplify,

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8 0
2 years ago
A pyramid-shaped vat has square cross-section and stands on its tip. The dimensions at the top are 2 m × 2 m, and the depth is 5
Strike441 [17]

Answer:

the water level increases at a rate of 1.718 m/min when the depth is 4 m

Step-by-step explanation:

the volume of the pyramid is

V = (1/3)(height)(area of base) = 1/3 H*L²

For the diagonal in the pyramid

tg Ф = Side Length/ Height = L / H = x / h

where h= depth of water , x= side of the corresponding cross section

therefore x= L *h/H

the volume of the water is

v= 1/3 h*x² = 1/3 (L/H)² h³

in terms of time

v = Q*t

then

Q*t = 1/3 (L/H)² h³

h³ = 3*(H/L)² *Q *t

h = ∛(3*(H/L)² *Q *t) = ∛(3*(H/L)² *Q) *∛t = k* ∛t , where k=∛(3*(H/L)² *Q)

h = k* ∛t

then the rate of increase in depth is dh/dt

dh/dt = 1/3*k* t^(-2/3)

since

t = (h/k)³

dh/dt = 1/3*k* t^(-2/3) = 1/3*k* (h/k)³ ^(-2/3)  = 1/3*k* (h/k)^(-2) = 1/3 k³ / h²

=  1/3 (3*(H/L)²*Q) / h²  = (H/L)²*Q /h²

dh/dt= [H/(h*L)]²*Q

replacing values, when h=4m

dh/dt= [H/(h*L)]²*Q  = [5m/(4m*2m)]² * (3m³/min)= 1.718 m/min

8 0
3 years ago
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