Answer:
2.498g
Explanation:
First off it's important to know Avogadro's number relationship with number of moles and molar mass.
It is given as;
1 mole = 6.02 * 10^23 atoms.
A mole's weight is equal to it's molar mass. Hence the equation can be changed to;
1 mole = molar mass = 6.02 * 10^23 atoms
In this problem, molar mass of Sulphur is 32g/mol. This means 1 mole of sulphur weighs 32 g and contains 6.02 * 10^23 atoms. What mass of sulphur would then contain 4.7x10^22 of atoms?
This leads us to;
32 g = 6.02 * 10^23
x g = 4.7x10^22
Upon cross multiplication, we have;
x = (4.7x10^22 * 32) / 6.02 * 10^23
x = 24.98 * 10^-1
x = 2.498g
Answer:
For each of the salts on the left, match the salts on the right that can be compared directly, using Ksp values, to estimate solubilities. (If more than one salt on the right can be directly compared, include all the relevant salts by writing your answer as a string of characters without punctuation, e.g, ABC.) fill in the blank 1 1. manganese(II) sulfide A. CuS fill in the blank 2 2. calcium fluoride B. FeS C. PbCl2 D. CaCrO4 Write the expression for K in terms of the solubility, s, for each salt, when dissolved in water. manganese(II) sulfide calcium fluoride Ksp
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