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uranmaximum [27]
4 years ago
10

A solution is prepared by dissolving 2.61 g ethanol (C2H5OH) in 16.2 g water. What is the molality (mol/kg) of C2H5OH in the sol

ution?
Chemistry
1 answer:
stiks02 [169]4 years ago
7 0

Answer:

3.50 molal

Explanation:

Molality → Moles of solute / kg of solvent.

Let's convert the solvent's mass from g to kg

16.2 g . 1kg / 1000 g = 0.0162 kg

Let's determine the moles from the solute

2.61 g . 1 mol / 46 g = 0.0567 moles

Molality → 0.0567 mol / 0.0162 kg = 3.50 m

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That would be the answer for a)

To know the P-32 remaining after 84 days we have to replace this value in the equation:

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