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4 years ago

Determine the difference between the mean and standard deviation of: 33, 44, 43, 56, 55, and 30.

Mathematics

1 answer:

lorasvet [3.4K]4 years ago

4 0

Answer:

mean = ( 33+44+43+56+55+30) / 6

= 261/6

= 43.5

$variance = \frac{33 { }^{2} + {44}^{2} + {43}^{2} + {56}^{2} + {55}^{2} + {30}^{2} }{6} - {43.5}^{2}$

variance = 96.92

standard deviation = √96.92

= 9.84

difference between mean and standard deviation

= 43.5 - 9.84

= 33.66

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