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3 years ago

If x is equal to 52 and y is equal to 10, then what is the value of x - 12y?

Mathematics

2 answers:

bearhunter [10]3 years ago

8 0

Answer:

-68

Step-by-step explanation:

x-12y

52-12x10

52-120

-68

oksano4ka [1.4K]3 years ago

6 0

Answer: -68

Step-by-step explanation: if x is equal to 52 and y is equal to ten you have to plug in the numbers for the variables so your equation comes out to 52-12*10 which simplifies to 52-120 which equals -68

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Round each number to the nearest ten. What is the best estimate for the answer to 343.42 – 39.87?

Nikolay [14]

So I would round it to 340 and 40 because if the number is lower than 5 than take it DOWN to the nearest ten if it's five or above take UP to the nearest ten

Hope it helped you

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4 years ago

C is the center of the circle. Find the area of the segment shown in the figure,

Semmy [17]

Answer: A 28.50 sq. u

Step-by-step explanation:

In the given figure , radius of the circle : r= 10 u

Central angle made by Arc ED: $\theta$ = 90° ( right angle )

Now , the area of the segment is given by :-

Area of segment = Area of sector (ECD) - Area of triangle(ECD) (i)

Formula : Area of right triangle = 0.5 x Base x Height

Area of sector = $\dfrac{\theta}{360^{\circ}}\times\pi r^2$

Using above formulas in (i) and substituting corresponding values , we get

Area of segment =

$\dfrac{90^{\circ}}{360^{\circ}}\times\pi (10)^2-0.5\times10\times10\\\\=\frac{1}{4}(3.14)(100)-50\\\\=78.5-50=28.5\ sq.u$

Hence, the correct answer is A 28.50 sq. u

6 0

3 years ago

The sum of a number and eight is doubled. the result is 12 more than the number.

Luda [366]

Sum means additions so n + 8 = (y)
2(y) = n + 12

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4 years ago

A 12 oz soda costs $1.25 in the vending machine. At that rate, how much would a<br> 48 oz soda cost?

Daniel [21]

Answer:

Step-by-step explanation:

48/12=4

1.25x4=5

Or you could set it up as a proportion

12/1.25=48/x

6 0

3 years ago

How many moles of hydrogen, H2, are needed to react with 2.0 moles of nitrogen, N2

Ber [7]

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3 years ago