$a_{n} \: = \: 2(a_{n - 1})^{2} \\ a_{1} = 4 \: (given) \\ a_{2} = \: 2(a_{2 - 1})^{2} \\ = 2(a_{ 1})^{2} \\ = 2 \times {4}^{2} \\ = 32 \\ \\ a_{3} = \: 2(a_{3 - 1})^{2} \\ = 2(a_{ 2})^{2} \\ = 2 \times {32}^{2} \\ = 2 \times 1024 \\ = 2048$

so first 3 terms are

4, 32, 2048

8 0

4 years ago

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Ill give brainliest to whoever answers 1st

salantis [7]

Answer:

0, 5, 8, 9, 8, 5, 0

Step-by-step explanation:

4 0

3 years ago

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11w +99 < 33 algebra answer

Otrada [13]

Answer:

w<-6

Step-by-step explanation:

11w+99<33

-99

11w<-66/11

3 0

3 years ago

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Y=3x + 4 Find the value of y when x=4

Sedaia [141]

Y = 16 because 4x3 = 12 + 4 = 16

7 0

3 years ago

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