Answer:
The 4th term is 7
Step-by-step explanation:
we have


step 1
Find C(2)
For n=2


step 2
Find C(3)
For n=3


step 3
Find C(4)
For n=4


therefore
The 4th term is 7
3.78/6= 0.63
$0.63 per bottle
42(0.63)= $26.46
I'll say the first integer is x. The next consecutive odd number would be x+2. If the sum of the odd integers is 236, the equation would be
x + (x + 2) = 236
solve for x
2x + 2 = 236
subtract 2 from each side of the equation
2x = 234
divide both sides by 2
x = 117
117 is the first odd integer. to find the other integer (x + 2), substitute 117 for x, and you have 117 + 2, which equals 119
The two consecutive odd integers that add up to 236 are 117 and 119.
Answer:
Step-by-step explanation:
what you need to do is look at the question again it say 10 feet above sea level and the other one is 7 feet below sea level. now read your question again hope you find the answer good luck
In an arithmetic sequence, the difference between consecutive terms is constant. In formulas, there exists a number
such that

In an geometric sequence, the ratio between consecutive terms is constant. In formulas, there exists a number
such that

So, there exists infinite sequences that are not arithmetic nor geometric. Simply choose a sequence where neither the difference nor the ratio between consecutive terms is constant.
For example, any sequence starting with

Won't be arithmetic nor geometric. It's not arithmetic (no matter how you continue it, indefinitely), because the difference between the first two numbers is 14, and between the second and the third is -18, and thus it's not constant. It's not geometric either, because the ratio between the first two numbers is 15, and between the second and the third is -1/5, and thus it's not constant.