Their final velocity is 0.48 m/s.
We can use conservation of momentum to calculate the magnitude of the final velocity.
Momentum before collision is equal to the momentum after collision
m1v1+m2v2=(m1+m2)v
here, v is final velocity , assuming right side velocity as positive, and left side velocity as negative.
14*(-1.1)+18*(0)=(14+18)v
v=-0.48 m/s
Here, negative sign indicates that they both will move in left direction.
As the intensity increases the energy increases.
Answer:
C. the energy of the sound wave increases
Complete question :
A 12 m x 15 m house is built on a 12-cm-thick concrete slab.
What is the heat-loss rate through the slab if the ground temperature is 5°C while the interior of the house is 25°C
Answer:
3kW
Explanation:
Given the following :
Dimension of house :
Length = 12m
Width = 15m
Thickness of concrete slab (t) = 12cm
t in metres :
100cm = 1m
12cm = (12/100)m
= 0.12m
Ground temperature (Tg) = 5°C
Interior temperature = (Th) = 25°C
Thermal conductivity of concrete (K) is approximately 1 Wm/k
Using the relation:
Q = KA * [ (Th - Tg) / d]
A = Length * width = (12 *15) = 180
Q = (1 * 180) * [(25°C - 5°C) / 0.12]
Q = 180 * (20/0.12)
Q = 180 * 16.6666
Q = 3,000W = 3kW
Answer:
Decrease the slit separation, increase the distance of the screen from the slits, and increase the wavelength.
Explanation:
The distance
from the central band to the first bright band is given by

where
is the wavelength of light (or any particle),
is the distance to the screen, and
is the slit separation.
From this equation we see that, by increasing the wavelength
, increasing the distance from the screen
, and decreasing the slit separation
, we increase the distance between the first bright band and the central band.
Therefore, the 2nd choice "<em>Decrease the slit separation, increase the distance of the screen from the slits, and increase the wavelength.</em>" is correct.
Given parameters:
Speed of car = 50m/s
Time of travel = 5minutes (300s)
Unknown;
Distance of travel = ?
To solve this problem, we need to understand how speed relates with distance and time.
Speed is a physical quantity. It is the distance traveled divided by time taken.
Speed = 
So,
Distance = speed x time
Input the parameters and solve for the distance;
Distance = 50m/s x 300s
Distance = 15000m
The distance covered during this time interval and speed is 15000m