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Softa [21]
4 years ago
15

The age of the universe in seconds

Physics
1 answer:
Marianna [84]4 years ago
7 0

Answer:

4.351968e+17 seconds

Explanation:

So I googled age of the universe and it says 13.8 billion years.

you'll have to do some conversions:

in one year, there are 365 days. in one day, there are 24 hours. in one hour, there are 3600 seconds.

\frac{1 year}{365 days} x \frac{1 day}{24 hours} x \frac{1 hour}{3600 seconds}

so you have to add in the current age of the universe to that equation:

\frac{x seconds}{13.8 bil years} x \frac{1 year}{365 days} x \frac{1 day}{24 hours} x \frac{1 hour}{3600 seconds}

arranged so that the proper "units" will read as "x seconds" at the end of the equation.

then you do the math to find x:

13.8 billion x 365 x 24 x 3600 = 4.351968e+17 seconds.

which would be 435,196,800,000,000,000 seconds

Hope this helps :)

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Freya has a mass of 14kg she is running at 1.1m/s to the left when she runs into Eric, who is standing still. Eric has a mass of
Lilit [14]

Their final velocity  is 0.48 m/s.


We can use conservation of momentum to calculate the magnitude of the final velocity.


Momentum before collision is equal to the momentum after collision


m1v1+m2v2=(m1+m2)v


here, v is final velocity , assuming right side velocity as positive, and left side velocity as negative.


14*(-1.1)+18*(0)=(14+18)v


v=-0.48 m/s


Here, negative sign indicates that they both  will move in left direction.



8 0
4 years ago
What happens as a result of an increase in the intensity of a sound wave?
larisa [96]

As the intensity increases the energy increases.

Answer:

C. the energy of the sound wave increases

8 0
3 years ago
Read 2 more answers
What is the heat-loss rate through the slab if the ground temperature is 5 ∘C while the interior of the house is 25 ∘C?
Gala2k [10]

Complete question :

A 12 m x 15 m house is built on a 12-cm-thick concrete slab.

What is the heat-loss rate through the slab if the ground temperature is 5°C while the interior of the house is 25°C

Answer:

3kW

Explanation:

Given the following :

Dimension of house :

Length = 12m

Width = 15m

Thickness of concrete slab (t) = 12cm

t in metres :

100cm = 1m

12cm = (12/100)m

= 0.12m

Ground temperature (Tg) = 5°C

Interior temperature = (Th) = 25°C

Thermal conductivity of concrete (K) is approximately 1 Wm/k

Using the relation:

Q = KA * [ (Th - Tg) / d]

A = Length * width = (12 *15) = 180

Q = (1 * 180) * [(25°C - 5°C) / 0.12]

Q = 180 * (20/0.12)

Q = 180 * 16.6666

Q = 3,000W = 3kW

3 0
4 years ago
How can the distance between the first bright band and the central band be increased in a double-slit experiment?
Strike441 [17]

Answer:

Decrease the slit separation, increase the distance of the screen from the slits, and increase the wavelength.

Explanation:

The distance y from the central band to the first bright band is given by

y = \dfrac{ \lambda D}{d}

where \lambda is the wavelength of light (or any particle), D is the distance to the screen, and d is the slit separation.

From this equation we see that, by increasing the wavelength \lambda , increasing the distance from the screen D, and decreasing the slit separation d, we increase the distance between the first bright band and the central band.

Therefore, the 2nd choice "<em>Decrease the slit separation, increase the distance of the screen from the slits, and increase the wavelength.</em>" is correct.

8 0
4 years ago
A car is traveling down the highway cruise control at 50m/s (this means its is traveling with a constant velocity NOT accelerati
lawyer [7]

Given parameters:

Speed of car = 50m/s

Time of travel = 5minutes (300s)

Unknown;

Distance of travel = ?

To solve this problem, we need to understand how speed relates with distance and time.

 Speed is a physical quantity. It is the distance traveled divided by time taken.

                Speed  = \frac{distance}{time}

   So,

                Distance  =  speed x time

Input the parameters and solve for the distance;

               Distance  = 50m/s x 300s

               Distance  = 15000m

The distance covered during this time interval and speed is 15000m

3 0
3 years ago
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