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2 years ago

Give a ghost story fit for a teen

Physics

1 answer:

natulia [17]2 years ago

6 0

Answer: ok so this is a true story when i was little and i always like telling story's so here it is...

Explanation: when i was little i had parents that weren't as good and our house was like scary and it had spiders and i was always scared of them so for Christmas me and my 2 sisters got a doll like a American doll and we got princesses and so my older sister Alexis got Cinderella and my other sister heaven she was the second oldest and she got the little mermaid Ariel and i got belle beauty and the beast and so it was getting late and so me and my sister heaven went to put our dolls away in a box and my sister Alexis wanted to put hers in our room we all share a room and a bed and so she decided to put it on this little princess make up dressing table(i found an image that what it kind of looked like ig) siting down and so everyone was sleeping except my older brother he was the oldest and so he wanted to tell my sister Alexis something and our room door was cracked open and before he went to check on her the doll moved and stand up and when down on the floor and walking in circles and my brother saw it and the doll stopped and the dolls head turned facing him and just drooped and so he ran in his room and stayed up all night till someone else woke up soo yea he never liked dolls never and now thats it i know it took ling but yea

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A robin in flight has 20.8 J of PE when it is 27.6 m high. What is the mass of the robin? (Unit = kg)

schepotkina [342]

Answer:

<h2> $\boxed{ \bold{ \purple{0.0769 \: kg \: }}}$ </h2>

Explanation:

$\sf{Potential Energy ( P.E ) \: = \: 20.8 \: joule}$

$\sf{distance \: = 27.6 \: metre}$

$\sf{mass = }$ ?

$\sf{acceleration \: due \: to \: gravity = 9.68 \: {metre \: per \: second}^{2} }$

Now, let's find the mass:

$\sf{PE \: = mass \times gravity \: \times \: distance}$

plug the values

⇒ $\sf{20.8 = m \times 9.8 \times 27.6}$

Multiply the numbers

⇒ $\sf{20.8 = 270.48 \: m}$

Swap the sides of the equation

⇒ $\sf{270.48m = 20.8}$

Divide both sides of the equation by 270.48

⇒ $\sf{ \frac{270.48m}{270.48} = \frac{20.8}{270.48} }$

Calculate

⇒ $\sf{0.0769}$ kg

Hope I helped!

Best regards!!

7 0

2 years ago

Read 2 more answers

If a car skids 66 ft on wet concrete, how fast was it moving when the brakes were applied? (Round your answer to the nearest who

Sonbull [250]

Answer:

If a car skids 66 ft on wet concrete, it will move at 243 ft/s when the brake is applied.

Explanation:

To determine how fast the car was moving, after skidding, the formula below is used:

V = √32*fd

V is the car's speed (ft/s)

d is skid length (ft) = 66 ft

f is the coefficient of friction determined by the material the car was skidding on.

Coefficient of friction for wet concrete is 0.65

V = √32*fd

V = √32 *0.65* 66

V = 242.679 ft/s ≅ 243 ft/s (nearest whole number)

If a car skids 66 ft on wet concrete, it will move at 243 ft/s when the brake is applied.

8 0

3 years ago

Which of the following quantities provide enough information to calculate the tension in a string of mass per unit length μ that

Bad White [126]

Answer:

A. the wave speed v and Wavelength

Explanation:

Given that

Mass density per unit length=μ

Frequency = f

The velocity V given as

$\mu=\dfrac{T}{V^2}\ kg/m$

$V=\sqrt{\dfrac{T}{\mu}}$

T=Tension

V=Velocity

V= f λ

λ=Wavelength

Therefore to find the tension ,only wavelength and speed is required.

The answer is A.

8 0

3 years ago

Albert uses as his unit of length (for walking to visit his neighbors or plowing his fields) the albert (a), the distance albert

True [87]

To solve this problem, we know that:

1 Albert = 88 meters

1 A = 88 m

The first thing we have to do is to square both sides of the equation:

(1 A)^2 = (88 m)^2

1 A^2 = 7,744 m^2

<span>Since it is given that 1 acre = 4,050 m^2, so to reach that value, 1st let us divide both sides by 7,744:</span>

1 A^2 / 7,744 = 7,744 m^2 / 7,744

(1 / 7,744) A^2 = 1 m^2

Then we multiply both sides by 4,050.

(4050 / 7744) A^2 = 4050 m^2

0.523 A^2 = 4050 m^2

<span>Therefore 1 acre is equivalent to about 0.52 square alberts.</span>

7 0

3 years ago

Explain how wind acts as an agent of erosion and deposition

Maksim231197 [3]

Wind acts as an agent of Erosion and deposition because it can erode the sediments from the rock etc then deposit it someplace else

7 0

2 years ago