A bicyclist is traveling at +25 m/s when he begins to decelerate at -4 m/s2. How fast is he traveling after 5 seconds?
1 answer:
Answer:
<em>The bicyclist goes at 5 m/s</em>
Explanation:
<u>Motion With Constant Acceleration </u>
It's a type of motion in which the velocity of an object changes uniformly in time.
The equation that rules the change of velocities is:
Where:
a = acceleration
vo = initial speed
vf = final speed
t = time
It's given a bicyclist is traveling at v0=+25 m/s and decelerates at . We are required to calculate the speed after t=5 seconds.
Applying the formula:
The bicyclist goes at 5 m/s
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To solve this problem we will apply the concepts of energy conservation and Newton's second law that defines force as the product of the object's mass with its acceleration. Additionally we will apply concepts related to the kinematics equations of linear motion.
For conservation of energy we have that work is equal to kinetic energy therefore,
Here,
F = Force
d = Displacement
m = Mass
v= Velocity
At the same time we have the relation of
Therefore the value of the force can be interpreted as the rate of increase in energy per unit of distance, which makes it equivalent to
Applying Newton's Second Law
In 4 seconds final velocity of the object becomes
Then the work done is equal to,
Then the displacement is,
Therefore the distance moved is 16m