Question

A bicyclist is traveling at +25 m/s when he begins to decelerate at -4 m/s2. How fast is he traveling after 5 seconds?

Answer 1

Answer:

The bicyclist goes at 5 m/s

Explanation:

Motion With Constant Acceleration

It's a type of motion in which the velocity of an object changes uniformly in time.

The equation that rules the change of velocities is:

$v_f=v_o+at$

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

It's given a bicyclist is traveling at v0=+25 m/s and decelerates at $a=-4\ m/s^2$. We are required to calculate the speed after t=5 seconds.

Applying the formula:

$v_f=25+(-4)*5$

$v_f=25-20=5$

$v_f=5\ m/s$

The bicyclist goes at 5 m/s