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3 years ago

A bicyclist is traveling at +25 m/s when he begins to decelerate at -4 m/s2. How fast is he traveling after 5 seconds?

Physics

1 answer:

Karo-lina-s [1.5K]3 years ago

4 0

Answer:

<em>The bicyclist goes at 5 m/s</em>

Explanation:

<u>Motion With Constant Acceleration </u>

It's a type of motion in which the velocity of an object changes uniformly in time.

The equation that rules the change of velocities is:

$v_f=v_o+at$

Where:

a = acceleration

vo = initial speed

vf = final speed

t = time

It's given a bicyclist is traveling at v0=+25 m/s and decelerates at $a=-4\ m/s^2$ . We are required to calculate the speed after t=5 seconds.

Applying the formula:

$v_f=25+(-4)*5$

$v_f=25-20=5$

$v_f=5\ m/s$

The bicyclist goes at 5 m/s

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