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Mkey [24]
3 years ago
14

A star that appears to pulsate is called a

Physics
1 answer:
Kay [80]3 years ago
8 0
A star that appears to pulsate is called a Variable Star.
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3 years ago
9. How is spring potential energy determined from a force versus position graph?
kolezko [41]

Answer: The potential energy associated with a mass attached to a spring depends on how much the spring is stretched or compressed. ... The gravitational force on the mass is −mg (“−” because the force points down). The force is the negative of the slope on the potential energy versus position graph.

Explanation:

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3 years ago
A glider is initially moving at a constant height of 3.72 m. It is suddenly subject to a wind such that its velocity at a later
My name is Ann [436]

Answer:

17.89\ \text{m/s}

Explanation:

Velocity is given by

v(t) = 16.02\hat{i}-7.96(1 + t)\hat{j} + 0.76t^3\hat{k}

Initial velocity is asked so t = 0

v(0)=16.02\hat{i}-7.96(1+t)\hat{j}+0.76\times 0\hat{k}\\\Rightarrow v(0)=16.02\hat{i}-7.96\hat{j}

Magnitude is given by

|v|=\sqrt{16.02^2+(-7.96)^2}\\\Rightarrow |v|=17.89\ \text{m/s}

The initial velocity of the glider was 17.89\ \text{m/s}.

5 0
3 years ago
How can artists suggest volume with light?
Dimas [21]

Answer:

The answer is they utilized light in a few spots to enlighten the subjects and to demonstrate their volume as masses.  

Explanation:

That is the reason every one of the particles that move at the speed of light (e.g. photons) have zero rest mass. As a molecule with mass methodologies the speed of light, its vitality increments and winds up unbounded at the speed of light, which is the motivation behind why it can never be quickened to achieve that speed. However, you can state that the photon has relativistic mass on the off chance that you truly need to. In current wording, the mass of a protest is its invariant mass, which is zero for a photon.

5 0
3 years ago
A horizontal rectangular channel has a discharge per unit channel width of 8.0 m2 /s. In a hydraulic jump occurring in this chan
Mandarinka [93]

Answer:

Energy loss ΔE = 8.08  (Approx)

Explanation:

Given:

Channel width = 8 m/s²

Before jump a1 = 0.50 m

After jump a2 = 4.75 m

Find:

Energy loss ΔE

Computation:

Energy loss ΔE = (a2 - a1)³ / 4a1a2

Energy loss ΔE = (4.75 - 0.50)³ / 4(4.75)(0.50)

Energy loss ΔE = 76.7656 / 9.5

Energy loss ΔE = 8.08  (Approx)

8 0
3 years ago
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