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3 years ago

Which substance form a homogenous mixture when mixed with water?

Physics

2 answers:

Kitty [74]3 years ago

5 0

Explanation:

A mixture in which solute particles will completely dissolve in a uniform composition throughout the solution is known as a homogeneous mixture.

For example, when salt (NaCl) is dissolved in water then it completely dissolves throughout the given volume of water.

When particles of a solute are microscopically dispersed in a dispersion medium then it is known as collide. For example, milk is a collide.

A heterogeneous mixture is a mixture in which solute particles do not dissolve in a solvent and they are non-uniformly distributed in the solution.

For example, mud, cement, iron fillings in water will all form a heterogeneous solution.

When solute particles due to their large size do not dissolve in the solvent then this type of solution is known as suspension. For example, vinegar in water is a suspension.

Thus, we can conclude that salt is the substance that form a homogenous mixture when mixed with water.

Dmitrij [34]3 years ago

3 0

Corn oil is homogeneous, Whitevinegar is homogeneous. A sugar solution is homogeneous since only a colorless liquid is observed. Air with no clouds is homogeneous. ... A solution is a mixture of two or more substances in a single phase.

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3 years ago

Drag and drop the terms at the left to match the appropriate descriptions at the right. ResetHelp Visual acuity Emmetropia Accom

Lubov Fominskaja [6]

Answer: Visual acuity: sharpness of vision.

Myopia: nearsightedness

Refraction: bending of light rays.

Emmetropia: normal vision.

Accommodation: changes the shape of the eye lens to focus light on the retina.

Presbyopia: age-related farsightedness due to loss of elasticity in the lens.

Astigmatism: reduction in visual acuity due to changes in the cornea or lens.

Hyperopia: farsightedness

Myopia and hyperopia are refractive errors of the eye.

Presbyopia occurs in old age people.

Explanation:

Visual acuity: It can be defined as the inability to observe the details of shape of the object. Person loses sharpness in vision.

Myopia: It is a defect in vision in which person is able to observe the near by objects clearly but not able to see the distant objects.

Refraction: It can be defined as the bending of beam of light when it passes through from one substance to another.

Emmetropia: It is a vision without any defect.

Accommodation: It is the ability of the eye to adjust its focal length and adjusting the light on focus.

Presbyopia: It can be defined as the loss of ability of eye to focus on the object. It occurs in old age.

Astigmatism: It is a refractive error in which the eye does not focus light on retina.

Hyperopia: It is also called as farsightedness. Distant objects can be seen clearly but nearby appears blurry.

5 0

3 years ago

What is the meaning of friend ?

MakcuM [25]

Answer:

person that you know and like (not a member of your family), and who likes you

6 0

3 years ago

Calculate the energy equivalent in joules of the mass of a proton

Tamiku [17]

The problem should only have one part to it, but this one has two.
Before I can do the mass/energy conversion, I have to go and
look up the proton mass for myself ... go out and collect the straw
to make my bricks, as it were. As if the fabulous bounty of 7 points
makes it worth it. They make us do everything around here.

OK. In my Physics book⁽¹⁾, the proton rest mass is

   1.67 x 10⁻²⁷ kg.

The formula that relates mass to the equivalent energy is

E = m c² .

The method of applying the formula is known as "plug in what you know",
as follows:

   E = (mass) x (speed of light)²

= (1.67 x 10⁻²⁷ kg) x (3 x 10⁸ m/s)²

   = (1.67 X 10⁻²⁷ Kg) x (9 x 10¹⁶ m²/s²)

=    (1.5 x 10⁻¹⁰) (kg-m²/s²)

=    1.5 x 10⁻¹⁰ joule .
____________________________________

⁽¹⁾ Halliday, David and Resnick, Robert, Physics , John Wiley & Sons,
Inc., 1960, inside front cover, "SELECTED PHYSICAL CONSTANTS".

8 0

4 years ago

As a system expands, it absorbs 52.5 J of energy in the form of heat from the surroundings. The piston is working against a pres

Kaylis [27]

Answer:

Vi = 0.055 m³ = 55 L

Explanation:

From first Law of Thermodynamics, we know that:

ΔQ = ΔU + W

where,

ΔQ = Heat absorbed by the system = 52.5 J

ΔU = Change in Internal Energy = -102.5 J (negative sign shows decrease in internal energy of the system)

W = Work Done in Expansion by the system = ?

Therefore,

52.5 J = - 102.5 J + W

W = 52.5 J + 102.5 J

W = 155 J

Now, the work done in a constant pressure condition is given by:

W = PΔV

W = P(Vf - Vi)

where,

P = Constant Pressure = (0.5 atm)(101325 Pa/1 atm) = 50662.5 Pa

Vf = Final Volume of System = (58 L)(0.001 m³/1 L) = 0.058 m³

Vi = Initial Volume of System = ?

Therefore,

155 J = (50662.5 Pa)(0.058 m³ - Vi)

Vi = 0.058 m³ - 155 J/50662.5 Pa

Vi = 0.058 m³ - 0.003 m³

7 0

4 years ago