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3 years ago

Protons, neutrons, electrons, and a nucleus are

Physics

1 answer:

tatuchka [14]3 years ago

8 0

It would be Atoms, they’re all made up of these tiny particles

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A balloon-powered car rolls across the floor at a speed of 0.711 m/s. How long does it take to cover 8.25 m?

devlian [24]

Answer:

Time = 11.60 seconds.

Explanation:

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the equation;

$Speed = \frac{distance}{time}$

Given the following data;

Speed = 0.711m/s

Distance = 8.25m

To find the time;

Making time the subject of formula, we have;

$Time = \frac{distance}{speed}$

Substituting into the equation, we have;

$Time = \frac{8.25}{0.711}$

Time = 11.60 secs.

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3 years ago

What player(s) can take a goal kick?

inysia [295]

Answer:

c) goalie

Explanation:

8 0

3 years ago

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PLEASE HELP ME IF YOU KNOW STUFF ABOUT ENERGY TYSM

Tomtit [17]

Answer:

Kinetic Energy
Potential energy

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3 years ago

Read 2 more answers

Question - Does gum affect a student's performance in school?

Mars2501 [29]

Independent variable: the interdependent variable in this example, could be a number of things but the main one is what type of brand is the gum and what kind is it.

Dependent variable: the dependent variable is what you are trying to find so in this case, you are trying to find does gum affect a student's performance.This is the Dependent variable.

Hope I helped!

Have a nice day,

scollier1607

3 0

3 years ago

A baseball of mass m = 0.31 kg is spun vertically on a massless string of length L = 0.51m. The string can only support a tensio

natulia [17]

Given data:

* The mass of the baseball is 0.31 kg.

* The length of the string is 0.51 m.

* The maximum tension in the string is 7.5 N.

Solution:

The centripetal force acting on the ball at the top of the loop is,

$\begin{gathered} T+mg=\frac{mv^2}{L}_{} \\ v^2=\frac{L(T+mg)}{m} \\ v=\sqrt[]{\frac{L(T+mg)}{m}} \end{gathered}$

For the maximum velocity of the ball at the top of the vertical circular motion,

$v_{\max }=\sqrt[]{\frac{L(T_{\max }+mg)}{m}}$

where g is the acceleration due to gravity,

Substituting the known values,

$\begin{gathered} v_{\max }=\sqrt[]{\frac{0.51(7.5_{}+0.31\times9.8)}{0.31}} \\ v_{\max }=\sqrt[]{\frac{0.51(10.538)}{0.31}} \\ v_{\max }=\sqrt[]{17.34} \\ v_{\max }=4.16\text{ m/s} \end{gathered}$

Thus, the maximum speed of the ball at the top of the vertical circular motion is 4.16 meters per second.

8 0

1 year ago